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4 years ago

Please help on this physics question

Physics

1 answer:

morpeh [17]4 years ago

7 0

Answer:

you need to include the units for both axis to be able to answer this

Explanation:

average speed in uniform motion is the slope anywhere on the line but you could always pick 2 points and do it that way and speed is just rise over run

or y2-y1/x2-x1

Pick two points on the line and determine their coordinates.

Determine the difference in y-coordinates of these two points (rise).

Determine the difference in x-coordinates for these two points (run).

Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

the second bit i think they are looking for this calculation y = mx + b, where m is the slope and b is the y-intercept (where the line crosses the y axis (the vertical one that has no units

Then use that formula for the last question and put in the x value of 10 and complete the formula to find out what y is

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Physics students use a spring scale to measure the weight of a piece of lead. The experiment was performed two times: once in th

Lady_Fox [76]

Answer:

The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.

Explanation:

Knowing that the density of lead is $11,3 g/cm^{3}$ and the volume, we can calculate the true weight of the piece of lead:

$weight_{lead}=\rho _{lead}*V_{lead}=11,3 g/cm^{3} *50 cm^{3} = 565 g$

When the experiment is done in air, we can discard buoyancy force (due to different densities) made by air because it's negligible and the measured weight is approximately the same as the true weight.

When it is done in water, the effect of buoyancy force (force made by the displaced water) is no longer negligible, so we have to take it into account.

Knowing that the density of water is 1 g per cubic centimeter, and that the volume displaced is equal to the piece of lead (because of its much higher density, the piece of lead sinks), we can know that the buoyancy force made by water is 50 g, opposite to the weight of the lead.

$Weight_{measured}=weight_{lead}-weight_{water}=\frac{(565 g *9.8 m/s^{2} -50 g*9.8 m/s^{2})}{9,8m/s^{2} } = 515 g$

Now that we have the two measurements, we can calculate the difference:

$Difference= |Weight _{in water}- Weight _{in air}|=|515 g-565 g|=50 g$

The reading of the experiment made in air is 50 g more than the reading of the measurement made in water.

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3 years ago

When developing an experimental design, which action could a scientist take

NNADVOKAT [17]

Answer:

B.Include as many details as possible when writing the conclusion.

This helps improve the quality of their experiment..

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3 years ago

A white pool ball of mass 1.0 kg moving at 10 m/s collides with

solniwko [45]

The velocity of the red ball after the collision is 5.8 m/s

Explanation:

In absence of external forces on the system, we can apply the principle of conservation of momentum. The total momentum of the system must be conserved before and after the collision, so we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where:

$m_1 = 1.0 kg$ is the mass of the pool ball

$u_1 = 10 m/s$ is the initial velocity of the pool ball

$v_1 = 3.0 m/s$ is the final velocity of the pool ball

$m_2 = 1.2 kg$ is the mass of the red ball

$u_2 = 0$ is the initial velocity of the red ball

$v_2$ is the final velocity of the red ball

Solving the equation for v2, we find the final velocity of the red ball after the collision:

$v_2 = \frac{m_1 u_1-m_1v_1}{m_2}=\frac{(1.0)(10)-(1.0)(3.0)}{1.2}=5.8 m/s$

Learn more about collisions:

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3 years ago

Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc

romanna [79]

Answer:

a) The speed of the electron as it reaches the inner conductor is closest to:

v = 1.45 × 10⁷m/s

b) The electric field magnitude between the cylinders is

E = 10,000V/m

Explanation:

given

inner radius of the cylinder r₁ = 20mm = 0.02m

outter radius of the cylinder r₂ = 80mm = 0.08m

potential difference V= 600V

mass of electron = 9.1×10⁻³¹kg

charge on electron = 1.6×10⁻¹⁹C

calculating the work done in bringing electron at inner conductor is

$W =\frac{1}{2}mv^{2}$

note:

$V = \frac{W}{q}$

∴W = (ΔV)q

(ΔV)q = $\frac{1}{2}mv^{2}$

(600)1.6×10⁻¹⁹ = ¹/₂ × 9.1×10⁻³¹ × v²

v² ≈ 2.11 × 10¹⁴

v = 1.45 × 10⁷m/s

According to the energy conservation law, the total energy of an isolated system is always constant.

The energy of an isolated system can neither be created nor be destroyed, it can only convert one form to another form.

∴ the maximum electric field

E = ΔV/d

E = 600/d

where d is the distance between the two points

where d = 0.06m

E = 600/0.06

E = 10,000V/m

Note: the electric field due to the potential difference between to points depends upon the potential difference V and the distance between both points d.

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3 years ago

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zysi [14]

Answer:

B. Electrical to kinetic

Explanation

Since the mixer uses electricity to function, which in turn spins the blades, it converts electricity into kinetic energy.

HOPE IT HELPS U...

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4 years ago

Read 2 more answers