Question

A 2.75 kg block is pulled across a flat, frictionless floor with a 5.11 N force directed 53.8° above horizontal. What is the total force acting on the block? (total force = N)

Answer 1

Answer:

F = 3.01 N

Explanation:

Given that,

Mass of a block, m = 2.75 kg

Force applied to the block, F = 5.11 N

It is directed 53.8° above horizontal.

We need to find the total force acting on the block. The force acting on it is given by :

$F=F\cos\theta\\\\F=5.11\times \cos53.8\\F=3.01\ N$

So, 3.01 N of force is acting on the block.