All categories

3 years ago

Two circles are concentric if they have the same center.

Mathematics

1 answer:

Tpy6a [65]3 years ago

3 0

9514 1404 393

Answer:

(b) (x – 4)^2 + (y – 6)^2 = 16

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

You want the equation for a circle with center (4, 6) and radius 4. That equation is ...

(x -4)^2 +(y -6)^2 = 16

You might be interested in

Pls help with this math

eimsori [14]

The answer is B) 27

If explanation is needed, let me know

5 0

3 years ago

Read 2 more answers

The line has the same slope as 3x-y=5 and the same y-intercept as the graph of 4y-7x=16

ArbitrLikvidat [17]

Well standard form is Ax+By=C, so just move the -7x to the front so -7x+47=16

3 0

3 years ago

In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=9, and AC=12, find HC.

pickupchik [31]

Answer:

Step-by-step explanation:

It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get

$(AC)^{2}=(AB)^{2}+(BC)^{2}$

$(12)^{2}=(9)^2+(BC)^2$

$144=81+(BC)^2$

$(BC)^2=63$

$BC=\sqrt{63}$

Now, From ΔABC and ΔHBC, we have

∠ABC=∠BHC(each90)

∠ACB=∠HCB (Common)

By AA similarity, ΔABC is similar to ΔHBC.

Thus, using the similarity condition, we get

$\frac{HC}{BC}=\frac{BC}{AC}$

$\frac{HC}{\sqrt{63}}=\frac{\sqrt{63}}{12}$

$HC=\frac{63}{12}=\frac{21}{4}$

7 0

3 years ago

Calculate the factorization 16w^2+48w+36=(4w+[1])^2

stiv31 [10]

Answer:

[1] = 6

x = -3/2 is the root

Step-by-step explanation:

A perfect square trinomial is of the form ...

(a + b)² = a² +2ab +b²

You have ...

a²=16w² ⇒ a = 4w
b² = 36 ⇒ b = 6
2ab = 2(4w)(6) = 48w

Then the factorization is ...

16w² +48w +36 = (4w +6)²

This will be zero when x = -6/4 = -3/2.

3 0

3 years ago

Complete the square in the quadratic equation in order to write the equation in vertex form.y = x^2 - 6x - 8

Vesna [10]

Sent a picture of the solution.

4 0

3 years ago