The awenser of the problem is A
The small number is 2.
The large number is 3.
<u>Step-by-step explanation:</u>
Let the two consecutive numbers be x and x+1.
- x be the small integer.
- x+1 be the large integer.
The sum of these two consecutive integers = small integer + large integer
The sum of these two consecutive integers is x+x+1 = (2x+1)
It is given that,
- The sum of two consecutive integers is one less than three times the smaller integer.
- This means that, (2x+1) is one less than three times the smaller integer.
- Here, the small integer is represented as x.
<u>Therefore, it can determined that :</u>
(2x+1) = 3x-1
Keeping x term on one side and constants on other side,
3x-2x = 1+1
x = 2
Therefore, the small number is 2 and the large number is x+1 = 3.
Answer:
10
Step-by-step explanation:
The formula is
the square root of y1-y2 +x1-x2 (square root of everithing)
(-11)-(-1) + 0-0
(-11) - (-1) = -11 +1 = -10 0-0 = 0
The quare root of 10 squared is 10
Answer:
18.84
Step-by-step explanation:
2
r/2 is the circumference of half a circle. The radius is 6.
2(3.14)(6)/2 = 18.84
