The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change, slope or gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
2x- y = 3
y - x = 1
Make y the subject in the second equation, by adding x to both sides of the equation
y - x + x = x + 1
This gives
y = x + 1
Substitute y = x + 1 in 2x- y = 3
2x- x - 1 = 3
Evaluate the like terms
x = 4
Substitute x = 4 in y = x + 1
y = 4 + 1
Evaluate
y = 5
Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
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Answer:
38
Step-by-step explanation:
5x-7=3x+ll
5x=3x+18
2x/2=18/2
x =9
5 x 9 -7 = 36
3 x 9 + 11=36
m D =36
Just multiply 30 times 2,000 and also multiply 30 times 700. The reason you will multiply it by 30 is because in 1 month there is 30 days. 30 x 2,000= 60000 30 x 700 = 21000 I’m only 9 btw so sorry if I didn’t give a lot of detail lol
Answer:
By solving the equation 
we found that 
<u>Explanation: </u>
Given equation,
to find x
Step: 1 Cross multiply the denominators 2(x-5)=6(x+6)
Step: 2 Open brackets and simplify the term 2x-10=6x+36
Step: 3 Bring x terms on one side and simplify the equation the equation obtained is following,
2x-6x=36+10
-4x=46
Therefore, we solved x value from the given equation as .
A) No, the root 3 has multiplicity of 3.
B) No, there are two imaginary solutions.
C) No, the root −2 has multiplicity of 3.
D) Yes, the Fundamental Theorem of Algebra does not apply to this equation.
