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loris [4]
3 years ago
8

How many atoms of S are there in the reactants? Sg + F2 ---> SFO

Chemistry
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

One atom

Explanation:

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12.5 mL of 0.280 M HNO3 and 5.0 mL of 0.920 M KOH are mixed. Is the resulting solution acidic, basic or neutral?
svlad2 [7]

Answer:

The resulting solution is basic.

Explanation:

The reaction that takes place is:

  • HNO₃ + KOH → KNO₃ + H₂O

First we <u>calculate the added moles of HNO₃ and KOH</u>:

  • HNO₃ ⇒ 12.5 mL * 0.280 M = 3.5 mmol HNO₃
  • KOH ⇒ 5.0 mL * 0.920 M = 4.6 mmol KOH

As <em>there are more KOH moles than HNO₃,</em> the resulting solution is basic.

8 0
3 years ago
The nucleus contains positively charged ___ and neutral ___ and makes up more than 99% of the mass of an atom.
Mashcka [7]

Answer:

ions

Explanation:

atoms because of the charge

5 0
3 years ago
Using the standard reduction potentials, Pb 2+(aq) + 2e– =&gt; Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– =&gt; Fe(s), E° = –0.44 V Zn
mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}

Fe(s) and Zn(s) will reduce Cr^{3+} to Cr

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with E_{red}^{0} value lower than 1.51 V will donate electron to Mn^{3+} and thus reduces Mn^{3+} to Mn^{2+}.

So, Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}.

Metal with E_{red}^{0} value lower than -0.40 V will donate electron to Cr^{3+} and thus reduces Cr^{3+} to Cr.

So, Fe(s) and Zn(s) will reduce Cr^{3+} to Cr.

6 0
3 years ago
Can someone show their work on how to do this: Calculate the number of moles of Al2O3 present in 23.87g. (Molar mass of Al2O3= 1
vodomira [7]

Answer:

0.234 moles

Explanation:

moles of Al2O3 = mass / molar mass

moles of Al2O3 = 23.87g / 102.0g/mol

moles of Al2O3 = 0.234 moles (to three significant figures)

6 0
3 years ago
What on earth is the oxidation number of N in N2H4?
Levart [38]
N₂H₄ :

N =  - 2  

H = + 1

 2 * ( -2 ) + ( 1 * 4 ) =  - 4 + 4 = 0

hope this helps!

5 0
3 years ago
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