Answer:
1,239,284pa
Explanation:
Assuming it's an ideal gas we use
PV=nRT
P=nRT/V
then we convert our Temperature into Kelvin
T=25+273.15 =298.12K
we convert our volume into M cubed
1.5L =0.0015 cubic meter
P=nRT/V
P= (0.75×298.12×8.314)/0.0015
P = 1,239,284pa
Answer is: <span>percent ionization of aqueous acetic acid solution is 0.341%.
c(CH</span>₃COOH) = 1.55 M.
Ka(CH₃COOH) = 1.8·10⁻⁵.
Chemical reaction: CH₃COOH ⇄ CH₃COO⁻ + H⁺.
[CH₃COO⁻] = [H⁺] = x.
[CH₃COOH] = 1.55 M - x.
Ka = [CH₃COO⁻] · [H⁺] / [CH₃COOH].
1.8·10⁻⁵ = x² / (1.55 M - x).
Solve quadratic equation: x = 0.0053 M.
percent of ionization:
α = 0,0053 M ÷ 1.55 M · 100% = 0,341%
H2O is the Bronsted-Lowry base because it accepts the hydrogen ion to become H3O after the reaction is complete.
First, you need to find the mass of 1 mol of sugar. Mass, or molar mass, can simply be found by adding the masses of the individual elements. These are given to you on the periodic table.

12 x 12.011 grams (molar mass of Carbon) = 144.132 g
22 x 1.008 grams (molar mass of Hydrogen) = 22.176 g
11 x 15.999 grams (molar mass of Oxygen) = 175.989 g
Add all of the pieces together.
144.132 g + 22.176 g + 175.989 g = 342.297 grams
So, if one mole has 342.297 grams, then 7.35 of that amount will be your answer.
342.297 g/mol x 7.35 mol = 2,515.88 grams