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Paraphin [41]
3 years ago
15

Which is common to the life cycles of both flowering and non-flowering plants?

Chemistry
2 answers:
andrew11 [14]3 years ago
7 0
Answer: STAY DORMANT
Explanantion: because staying dormant is a common circle of flowering and non flowering
Stolb23 [73]3 years ago
4 0

Answer:

2 stay dormant

bbdndndn

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Find the volume in milliliters of 2.00 mol of an ideal gas at 36°C and a pressure of 1120 torr.
hram777 [196]

Answer:

V = 34430 mL

Explanation:

Given data:

Volume in mL = ?

Number of moles of gas = 2.00 mol

Temperature = 36°C (36+273= 309K)

Pressure of gas = 1120 torr

Solution:

Formula:

PV = nRT

V = nRT/P

V = 2.00 mol ×62.4 torr • L/mol · K × 309K / 1120 torr

V = 38563.2 torr • L / 1120 torr

V = 34.43 L

L to mL

34.43 L ×1000 mL / 1 L

34430 mL

5 0
3 years ago
Write down your observations of what the pieces of cabbage in the images look like
N76 [4]
They all look like there decaying and was left out or sat inside too long
5 0
2 years ago
Which statements accurately describe volume? Check all that apply.
lesantik [10]
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8 0
3 years ago
Does the H₂SO4 solution contain ions?<br> O yes<br> O no
Artist 52 [7]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Ions .

If we see the reaction.

H2SO4 ==> 2H+ + (SO4)2-

Here you can see, H+ ( Hydrogen ions) and (SO4) 2- ( sulphate ions) are the ions when the H2SO4 is dissolved in water.

8 0
2 years ago
A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the te
Monica [59]
You can establish a system of two equation with two variables.

Varibles are:
V1 = volume of the 50% sugar solution
V2 = volumen of the 80% sugar solution

Equations:
Balance of sugar:

Sugar from 50% solution: 0.5*V1
Sugar from 80% solution: 0.8*V2
Sugar in the final solution (mix): 0.6 * 105 = 63

1) 0.5V1 + 0.8V2 = 63

Final volume = volume of 50% solution + volume of 80% solution

2) V1 + V2 = 105

From (2) V1 = 105 - V2

Substitue in (1)

0.5 (105 - V2) + 0.8 V2 = 63

52.5 - 0.5V2 + 0.8V2 = 63

0.3 V2 = 63 - 52.5

0.3 V2 = 10.5

V2 = 10.5/0.3
V2 = 35mL

V1 = 105 - 35 = 70 mL

Answer: 70 mL of the 50% solution and 35 mL of the 80% solution.
5 0
3 years ago
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