Answer:
Average rate of change over the interval 2<= x <= 5:
y = 3x + 5: 3
y = 3x^2 + 1: 21
y = 3^x: 78
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Step-by-step explanation:
2<= x <= 5
Average rate of change over the interval 2<= x <= 5:
<u>y = 3x + 5</u>
y(5) = 3(5) + 5 = 20
y(2) = 3(2) + 5 = 11
Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>
<u />
<u>y = 3x^2 + 1</u>
y(5) = 3(5^2) + 1 = 75 + 1 = 76
y(2) = 3(2^2) + 1= 13
Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>
<u />
<u>y = 3^x</u>
y(5) = 3^5 = 243
y(2) = 3^2 =9
Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>
Answer:
10
β
Step-by-step explanation:
We can find this two ways, first by seeing in the step after it, cosines are canceled out. Since you already have 10
β
on the next step, you can assume that (since only the cosines changed and the cosine next ot the blank was removed), the value is 10
β
.
You can also use double angle formulas from the previous step:
(sin(2β) = 2 sin(β) cos(β))and find that:
5 sin (2β) sin(β) = 5 * (2 sin(β) cos(β)) sin(β)) = (10 sin(β) sin(β)) cos(β) =
10
β
cos(β)
But since cos(β) is already present, we can see that the answer is 10
β
The answer to this question is side KL
So, We Need To Examine The Problem. So, We Know That We Need To Find The Volume Of A Rectangular Prism. We Also Know That The Dimensions Are 4.9 • 3.8 • 5.4.
So, We Need To Remember The Formula For Volume Of A Rectangular Prism.
V = B • W • H
So, we need to plug in the known values.
V = 4.9 • 3.8<span> • 5.4.
So, Lets Solve.
4.9 • 3.8 = 18.62
18.62 * 5.4 = 100.548 cm²
Now We Have:
V = 100.548cm²
It Rounds To 100.5cm²</span>
Answer:

Step-by-step explanation:
It could also be 
depending on how the problem is actually set up.