Answer:
Average rate of change over the interval 2<= x <= 5:
y = 3x + 5: 3
y = 3x^2 + 1: 21
y = 3^x: 78
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Step-by-step explanation:
2<= x <= 5
Average rate of change over the interval 2<= x <= 5:
<u>y = 3x + 5</u>
y(5) = 3(5) + 5 = 20
y(2) = 3(2) + 5 = 11
Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>
<u />
<u>y = 3x^2 + 1</u>
y(5) = 3(5^2) + 1 = 75 + 1 = 76
y(2) = 3(2^2) + 1= 13
Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>
<u />
<u>y = 3^x</u>
y(5) = 3^5 = 243
y(2) = 3^2 =9
Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>
Answer:
10
β
Step-by-step explanation:
We can find this two ways, first by seeing in the step after it, cosines are canceled out. Since you already have 10β on the next step, you can assume that (since only the cosines changed and the cosine next ot the blank was removed), the value is 10β.
You can also use double angle formulas from the previous step:
(sin(2β) = 2 sin(β) cos(β))and find that:
5 sin (2β) sin(β) = 5 * (2 sin(β) cos(β)) sin(β)) = (10 sin(β) sin(β)) cos(β) =
10β cos(β)
But since cos(β) is already present, we can see that the answer is 10β
The answer to this question is side KL
So, We Need To Examine The Problem. So, We Know That We Need To Find The Volume Of A Rectangular Prism. We Also Know That The Dimensions Are 4.9 • 3.8 • 5.4.
So, We Need To Remember The Formula For Volume Of A Rectangular Prism.
V = B • W • H
So, we need to plug in the known values.
V = 4.9 • 3.8<span> • 5.4.
So, Lets Solve.
4.9 • 3.8 = 18.62
18.62 * 5.4 = 100.548 cm²
Now We Have:
V = 100.548cm²
It Rounds To 100.5cm²</span>
Answer:
Step-by-step explanation:
It could also be 
depending on how the problem is actually set up.
