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Papessa [141]
3 years ago
7

A garden flower grows a total of 10 cm in July and August. Assuming that the flower grows at a consistent rate for a full year,

how much will the flower grow in a year?
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

9514 1404 393

Answer:

  60 cm

Step-by-step explanation:

July and August are 2 of the 12 months in the year. The growth for the year can be expected to be 6 times the growth in a 2-month period, so 60 cm.

_____

You could get down to particulars as to the number of days in those two months versus the total number of days in a year. You would have to specify whether it is a leap year. In a non-leap year, the growth might be ...

  365/(31+31) × 10 cm ≈ 58.9 cm

In a leap year, it would be 59.0 cm.

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masya89 [10]

Answer:

a. P(E) = 1033/ 2851=0.3623

P(R) = 854/2851=0.2995

P(D) = 964/2851=0.3381

P(E ∩ D) = P(E) +P(D)= 0.3623 +0.3381= 0.7004

(d)  0.423 158

Step-by-step explanation:

a. P(E) = 1033/ 2851=0.3623

P(R) = 854/2851=0.2995

P(D) = 964/2851=0.3381

(b) Are events E and D mutually exclusive?

Yes these events are mutually exclusive. If students are deferred they may be admitted later but not early.  Mutually Exclusive or disjoint events do not occur at the same time.

P(E ∩ D) = P(E) +P(D)= 0.3623 +0.3381= 0.7004

(c) For the 2,375 students who were admitted,  the probability that a randomly selected student was accepted during early admission is

P(E) = 1033/ 2851=0.3623

P(E) + P(D for later admission)  =0.3623 + 18%*0.3381

                                                    =0.3623 + 0.0609 = 0.423 158

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Simplified that is -2 which is the slope of the line

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X = 1

7 - 2(1) = 7 - 2 = 5
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