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Contact [7]
3 years ago
9

Calculate the number of joules of heat energy needed to increase the temperature of 25.0 g of metal from 21.0 ºC to 80.0 ºC. The

specific heat of the metal is 0.521 J/gºC.
Chemistry
1 answer:
Harman [31]3 years ago
7 0

Answer:

Q = 768.47 J

Explanation:

Given that,

Mass of the metal, m = 25 g

Initial temperature, T₁ = 21.0 ºC

Final temperature, T₂ = 80.0 ºC

The specific heat of the metal is 0.521 J/gºC.

We know that the heat released due to the change in temperature is given by :

Q=mc\Delta T\\\\=25\times 0.521\times (80-21)\\Q=768.47\ J

Hence, 768.47 J of heat energy will be needed.

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In one process, 6.05 kg of caf2 is treated with an excess of h2so4 and yields 2.85 kg of hf. calculate the percent yield of hf.
Kobotan [32]
 The %  yield  of Hf  is  91. 8%


calculation

% yield =  actual mass/ theoretical mass  x100
actual mass = 2.85 Kg

calculate the theoretical  mass
by first  write the equation for reaction

CaF2  +H2SO4  → 2HF  + CaSO4
find  the  moles  of CaF2  used
moles = mass/molar mass
mass = 6.05Kg   = 6.05 x1000 =6050 Kg
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moles= 6050/ 78 = 77.6 moles

by  use  of mole ratio between  CaF2  to HF  which  is  1:2 the  moles of HF is therefore = 77.6 x2 =155.2  moles of Hf

find the  theoretical mass  of HF = moles x  molar mass ( 1 +19=20g/mol)

=   155.2  moles x 20 g/mol = 3104 grams  = 3104 /1000 = 3.104 Kg

The % yield  is therefore  = 2.85 Kg/ 3.104 Kg x100 =  91.8%

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