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gogolik [260]
4 years ago
8

g On the basis of their respective pKa values, determine which is the stronger acid, acetic acid (pKa 5 4.7) or benzoic acid (ma

rgin; pKa 5 4.2). By what factor do their acidities differ?
Chemistry
1 answer:
ozzi4 years ago
5 0

Answer:

Benzoic acid is the stronger acid

Explanation:

Weak acids do not dissociate completely in the solution. They exists in equilibrium with their respective ions in the solution.

The extent of dissociation of the acid furnising hydrogen ions can be determined by using dissociation constant of acid (K_a).

Thus for a weak acid, HA

HA \rightleftharpoons A^- + H^+

The K_a is:

K_a= \frac{[A^-][H^+]}{[HA]}

The more the K_a, the more the acid dissociates, the more the stronger is the acid.

Also,

pK_a is defined as the negative logarithm of K_a.

So, more the pK_a, less is the K_a and vice versa

All can be summed up as:

The less the value of pK_a, the more the  K_a is and the more the acid dissociates and the more the stronger is the acid.

Given,

pK_a of acetic acid = 54.7

pK_a of benzoic acid = 54.2

pK_a of benzoic acid < pK_a of acetic acid

So, benzoic acid is the stronger acid.

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Given the balanced ionic equation:
bezimeni [28]

Answer : The correct option is, (4) 6.0 mol

Explanation :

The given balanced chemical equation is,

3Pb^{2+}+2Cr\rightarrow 3Pb+2Cr^{3+}

In this reaction, lead undergoes reduction and chromium undergoes oxidation.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

Half reactions of oxidation-reduction are :

Oxidation : 2Cr\rightarrow 2Cr^{3+}+6e^-

Reduction : 3Pb^{2+}+6e^-\rightarrow 3Pb

From the reduction reaction, we conclude that 6 moles of electrons gained by the 3 moles of lead ions.

Hence, the correct option is, (4) 6.0 mole

5 0
3 years ago
What is the hydrogen ion concentration of a solution with pH = 8.75 ?
Tom [10]

Answer:

The answer is 1.778*10^-9

Explanation:

Using the formula

pH = -log[H^+]

Since the pH of the solution has been given to be 8.75,

Therefore,

8.75= -log [H^+]

Let's take H^+ to be x

8.75= -log x

Let's look for x, since the log is in base 10

X = 10^-8.75

X = 1.778 * 10^ -9

Therefore, H^+ =1.778 *10^-9

4 0
4 years ago
An unknown compound contains only C , H , and O . Combustion of 5.60 g of this compound produced 13.7 g CO2 and 5.60 g H2O . Wha
son4ous [18]

Answer:

Empirical formula of compound  is C₄H₈O

Explanation:

Given data:

Mass of compound = 5.60 g

Mass of CO₂ = 13.7 g

Mass of H₂O = 5.60 g

Empirical formula of compound = ?

Solution:

Percentage of C:

13.7 g/5.60 g × 12/44× 100

2.45×0.273× 100 = 66.9%

Percentage of H:

5.60 g/ 5.60 g × 2.016/18 × 100

11.2%

Percentage of O:

(66.9% + 11.2%) - 100 = 21.9%

Grams atom of  C , H, O

66.9/12 = 5.6

11.2 / 1.008 = 11.11

21.9 / 16 = 1.4

Atomic ratio:

           C                 :               H           :              O

           5.6/1.4         :            11.11/1.4    :            1.4/1.4

              4                :               8            :               1

Empirical formula:

C₄H₈O

7 0
4 years ago
What is a unsaturated solution????
Viefleur [7K]
It doesn't have enough solute. So say someone likes sweet tea. If you were to add more sugar it would still dissolve no matter how much is in the glass. Sorry if this is confusing.
6 0
4 years ago
A balloon inflated in a room at 27 degrees celsius has a volume of 8.00 L.the balloon is then heated to a temperature of 78 degr
dangina [55]
This problem is being solved using Ideal Gas Equation.
                                                   PV  =  nRT
Data Given:
                  Initial Temperature = T₁ = 27 °C = 300 K
                  Initial Pressure      =  P₁ = constant
                  Initial Volume         = V₁ = 8 L
                   Final Temperature = T₂ = 78 °C = 351 K
                  Final Pressure      =  P₂ = constant
                  Final Volume         = V₂ = ?
As,
Gas constant R and Pressures are constant, so, Ideal gas equation can be written as,
                                          V₁ / T₁  =  V₂ / T₂
Solving for V₂,
                                           V₂  =  (V₁ × T₂) ÷ T₁
Putting Values,
                                           V₂  =  (8 L × 351 K) ÷ 300 K

                                           V₂  =  9.38 L
5 0
3 years ago
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