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gogolik [260]
3 years ago
8

g On the basis of their respective pKa values, determine which is the stronger acid, acetic acid (pKa 5 4.7) or benzoic acid (ma

rgin; pKa 5 4.2). By what factor do their acidities differ?
Chemistry
1 answer:
ozzi3 years ago
5 0

Answer:

Benzoic acid is the stronger acid

Explanation:

Weak acids do not dissociate completely in the solution. They exists in equilibrium with their respective ions in the solution.

The extent of dissociation of the acid furnising hydrogen ions can be determined by using dissociation constant of acid (K_a).

Thus for a weak acid, HA

HA \rightleftharpoons A^- + H^+

The K_a is:

K_a= \frac{[A^-][H^+]}{[HA]}

The more the K_a, the more the acid dissociates, the more the stronger is the acid.

Also,

pK_a is defined as the negative logarithm of K_a.

So, more the pK_a, less is the K_a and vice versa

All can be summed up as:

The less the value of pK_a, the more the  K_a is and the more the acid dissociates and the more the stronger is the acid.

Given,

pK_a of acetic acid = 54.7

pK_a of benzoic acid = 54.2

pK_a of benzoic acid < pK_a of acetic acid

So, benzoic acid is the stronger acid.

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The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equili
boyakko [2]

Answer:

ΔSv = 0.1075 KJ/mol.K

Explanation:

Binary solution:

∴ a: solvent

∴ b: solute

in equilibrium:

  • μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)

⇒ Ln (1 - Xb) = ΔG/RT

∴ ΔG = ΔHv - TΔSv

⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R

∴ Xb → 0:

⇒ Ln(1) = ΔHv/RT - ΔSv/R

∴ T = T*b....normal boiling point

⇒ 0 = ΔHv/RT*b - ΔSv/R

⇒ ΔSv = (R)(ΔHv/RT*b)

⇒ ΔSv = ΔHv/T*b

∴ T*b = 80°C ≅ 353 K

⇒ ΔSv = (38 KJ/mol)/(353 K)

⇒ ΔSv = 0.1075 KJ/mol.K

5 0
3 years ago
Which example is NOT a model?
lidiya [134]

Answer:

B

Explanation:

i think leter B it because

7 0
3 years ago
Read 2 more answers
Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl2) in 0.30 L of solution. SHOW YOUR
ycow [4]

Answer:

[CaCl₂] = 1.32 M

Explanation:

We know the volume of solution → 0.30 L

We know the mass of solute → 44 g of CaCl₂

Let's convert the mass of solute to moles.

44 g . 1 mol / 110.98 g = 0.396 moles

Molarity (mol/L) → 0.396 mol / 0.3 L  = 1.32 M

6 0
3 years ago
You have a mass of 54 kg and are sitting on a stool. The normal force the stool applies on you is ...
Karo-lina-s [1.5K]

Answer:

529.2 N

Explanation:

As we have studied the first law of motion, which states that every action has some reaction, equal in magnitude but having an opposite direction.

The force that is acting on the student will be due to gravitational force, that is equal to his weight.

                                              F=mg: 54kg x 9.8m/s^2 =529.2 N

So the weight of student is exerting downwards towards the stool and land. The stool will also exert a force on the student that will be equal in magnitude but opposite in direction, then it will be 529.2 N.

This is because the student is sitting in a constant state and all the weight is exerted on the stool.

Note: This answer is very generic supposing that all the weight of the student is on stool. But, if we suppose that student's legs are on floor so it means the force of gravity acting on the stool has become less because student's mass on stool is less. So the answer would be a force somehow less than 529.2 N.  However, since the question asked normal force, it would be weight of student in general terms.

Hope it helps!

7 0
3 years ago
A is more linear than wich
bekas [8.4K]
You should put a picture or finish the question
4 0
3 years ago
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