<u>Answer:</u> The mass percent of $Co^{3+},Cl^{-},H^+\text{ and }O^{2-}$ ions in the compound are 49.28 %, 29.79 %, 2.33 % and 18.63 % respectively

<u>Explanation:</u>

We are given:

Mass of silver chloride = 0.308 grams

Mass of cobalt (III) oxide = 0.145 grams

Mass of sample containing chloride ions = 0.256 grams

Mass of sample containing $Co^{3+}$ ions = 0.416 grams

We know that:

Molar mass of silver chloride = 143.4 g/mol

Molar mass of chlorine ion = 35.45 g/mol

Molar mass of cobalt (III) oxide = 165.86 g/mol

Molar mass of $Co^{3+}$ ion = 117.86 g/mol

Molar mass of water = 18 g/mol

Molar mass of hydrogen ion = 1 g/mol

Molar mass of oxygen ion = 16 g/mol

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To calculate the mass percentage of ions in sample, we use the equation:

$\text{Mass of ion}}{\text{Mass of sample}}\times 100$ .......(2)

<u>For chlorine ion:</u>

Calculating moles of AgCl by using equation 1:

Moles of AgCl = $\frac{0.308g}{143.4g/mol}=0.00215mol$

The chemical equation for the ionization of silver chloride follows:

$AgCl\rightarrow Ag^++Cl^-$

By Stoichiometry of the reaction:

1 mole of silver chloride produces 1 mole of chlorine ions

So, 0.00215 moles of silver chloride will produce = $\frac{1}{1}\times 0.00215=0.00215mol$ of chloride ions

Mass of chloride ions = $(0.00215mol\times 35.45g/mol)=0.0762g$

Putting values in equation 2, we get:

$\text{Mass percent of chloride ion}=\frac{0.0762g}{0.256g}\times 100\\\\\text{Mass percent of chloride ion}=29.76\%$

Mass percent of chloride ion = 29.76 %

<u>For $Co^{3+}$ ion:</u>

Calculating moles of cobalt (III) oxide by using equation 1:

Moles of cobalt (III) oxide = $\frac{0.145g}{165.86g/mol}=0.00087mol$

The chemical equation for the ionization of cobalt (III) oxide follows:

$Co_2O_3\rightarrow 2Co^{3+}+3O^{2-}$

By Stoichiometry of the reaction:

1 mole of cobalt (III) oxide produces 2 moles of cobalt ions

So, 0.00087 moles of cobalt (III) oxide will produce = $\frac{2}{1}\times 0.00087=0.00174mol$ of cobalt ions

Mass of cobalt ions = $(0.00174mol\times 117.86g/mol)=0.205g$

Putting values in equation 2, we get:

$\text{Mass percent of cobalt ion}=\frac{0.205g}{0.416g}\times 100\\\\\text{Mass percent of cobalt ion}=49.28\%$

Mass percent of cobalt ion = 49.28 %

<u>For hydrogen and oxygen ion:</u>

Calculating mass percent of water:

Mass percent of water = 100 - (29.76 + 49.28) = 20.96 %

Let the mass of compound be 100 grams. So, mass of water in the compound will be 20.96 g

<u>For hydrogen:</u>

In 18 grams of water, mass of hydrogen ion present is (1 × 2) = 2 g

So, in 20.96 grams of water, mass of hydrogen ion present will be = $\frac{2}{18}\times 20.96=2.33g$

Putting values in equation 2, we get:

$\text{Mass percent of hydrogen ion}=\frac{2.33g}{100g}\times 100\\\\\text{Mass percent of hydrogen ion}=2.33\%$

Mass percent of hydrogen ion = 2.33 %

<u>For oxygen:</u>

In 18 grams of water, mass of oxygen ion present is (16 × 1) = 16 g

So, in 20.96 grams of water, mass of oxygen ion present will be = $\frac{16}{18}\times 20.96=18.63g$

Putting values in equation 2, we get:

$\text{Mass percent of oxygen ion}=\frac{18.63g}{100g}\times 100\\\\\text{Mass percent of oxygen ion}=18.63\%$

Mass percent of oxygen ion = 18.63 %

Hence, the mass percent of $Co^{3+},Cl^{-},H^+\text{ and }O^{2-}$ ions in the compound are 49.28 %, 29.79 %, 2.33 % and 18.63 % respectively

7 0

3 years ago

Volume of water displaced = 94.60 cm3 Answer the following questions: Mass = g Density =

natita [175]

A 296.5 g.

Is your answer

3 0

4 years ago

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The length of the Amazon River in South America is 6,400 kilometers. What is the length written in scientific notation with the

maw [93]

Answer:

6,400 km = 6.4 x 10³ km.

Explanation:

Measurements => Scientific Notation.

Scientific notation is a way to express numbers as the product of two numbers: a coefficient and the number 10 raised to a power. The exponent must be a non-zero integer, it can be either positive or negative. The value of the coefficient is greater than or equal to 1 but it should be less than 10.

In this case, we request to write 6,400 kilometers in scientific notation. Based on the concept of scientific notation, our coefficient would be 6.4 because is greater than 1 and less than 10. 6,400 is a positive integer that contains 4 digits, so we have to multiply 6.4 by 1000 to obtain 6,400. 1000 equals 10³, so the 6,400 kilometers in scientific notation would be 6.4 x 10³ kiloem km.

4 0

1 year ago

Write an interesting good presentation of acid and base​

Write an interesting good presentation of acid and base