Which formula represents copper(I) oxide? (1) CuO (3) Cu2O (2) CuO2 (4) Cu2O2

Chemistry

2 answers:

mars1129 [50]3 years ago

6 0

Answer : The correct formula of copper(I) oxide is, (3) $Cu_2O$

Explanation :

Copper(I) oxide is an ionic compound because copper element is a metal and oxide element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The nomenclature of ionic compounds is given by:

Positive ion is written first.
The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

The charge on copper is (+1) and the the charge on oxide is (-2). The charges are not balanced. The charges are balanced by the criss-cross method.

Hence, the formula of copper(I) oxide is, $Cu_2O$

faust18 [17]3 years ago

3 0

The answer is (3) Cu2O. Copper (I) has an oxidation state of +1 (that's what the "I" indicates). You can also think of this as copper (I) having a charge of +1. Oxygen has an oxidation state of -2 (that's just a rule you have to know), and you can think of it as oxygen having a charge of -2. You need oxidation numbers in a neutral compound to add up to 0 (or charges in a neutral compond to add up to 0), so you need two Cu to balance the O, which is Cu2O.

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<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then