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devlian [24]
3 years ago
9

You have one test tube which contains a colorless solution that is either Cu+2 (aq) or Bi+3(aq). Select a reagent that will allo

w you to differentiate between the two chemical species. If the solution is Cu+2, what will happen when the reagent is added? If the solution is Bi+3, what will happen when the reagent is added?
Chemistry
1 answer:
Jlenok [28]3 years ago
8 0

Answer:

Explanation:

You can use KI and K4[Fe(CN)6].

When you add KI in a solution with only Cu2+ nothing will happen, but when you add K4[Fe(CN)6] it will form a solid of Cu2[Fe(CN)6] that will be reddish-brown.

When you add K4[Fe(CN)6] in a solution with only Bi3+ nothing will happen, but when you add KI it will form a solid of BiI3 that will be black.

So in a solution which contains both of then, you can add KI to determinate Bi3+, if you see a black solid. If nothing happens, you can affirme that it contains Cu2+.

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Gwar [14]
Hey there!

Volume in mL :

1.68 L  * 1000 => 1680 mL

Density = 0.921 g/mL

Therefore:

Mass = density * Volume

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KIM [24]

Answer:

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What mass of Cu(s) is electroplated by running 24.5A of current through a Cu2+(aq)solution for 4.00 h?Express your answer to thr
Masja [62]

Answer: 116 g of copper

Explanation:

Q=I\times t

where Q= quantity of electricity in coloumbs

I = current in amperes = 24.5A

t= time in seconds =  4.00 hr = 4.00\times 3600s=14400s  (1hr=3600s)

Q=24.5A\times 14400s=352800C

Cu^{2+}+2e^-\rightarrow Cu

2\times 96500C=193000C  of electricity deposits 63.5 g of copper.

352800 C of electricity deposits = \frac{63.5}{193000}\times 352800=116g of copper.

Thus 116 g of Cu(s) is electroplated by running 24.5A of current

Thus  remaining in solution = (0.1-0.003)=0.097moles

8 0
3 years ago
In the experiment, 40 mL of 3 M sodium hydroxide is used to extract the benzoic acid. In order to recover the benzoic acid from
nikdorinn [45]

Answer:

20 mL OF 6 M HYDROCHLORIC ACID WILL BE NEEDED

Explanation:

M1 V1 = M2 V2

M1 = Molarity of sodium hydroxide = 3 M

V1 = volume of sodium hydroxide = 40 mL

M2 = Molarity of hydrochloric acid = 6 M

V2 = Volume of hydrochloric acid = unknown

Rearranging the equation, we have:

V2 = M1 V1 / M2

V2 = 3 * 40 mL / 6

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V2 = 20 mL

To precipitate the benzoic acid by 6 M of hydrochloric acid, 20 mL volume will be needed.

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Marina86 [1]
D

A describes liquid, b describes solid, and c describes solid as well. therefore d is the only good answer
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3 years ago
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