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3 years ago

Evaluate l-a^2l, given a = 5, b = -3, and c= -2.

Mathematics

2 answers:

mash [69]3 years ago

6 0

THE ANSWER ISSS
25 WHICH IS C

dimulka [17.4K]3 years ago

3 0

I’m sorry bro I wish I knew

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NEED HELP ASP!!

balu736 [363]

D) 34/5 because 6(5) = 30 30+4=34 , so its 34/5

7 0

3 years ago

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juan and debbie each earn 9 per hour at their "jobs." Debbie worked five hours more than juan during the week. if juan and debbi

Vaselesa [24]

Using a system of equations, it is found that Debbie worked 45 hours during the week.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

Variable x: Amount of hours worked by Juan.

Variable y: Amount of hours worked by Debbie.

Juan and Debbie each earn 9 per hour at their "jobs", and earned a total of 765 for the week, hence:

9x + 9y = 765

Simplifying the expression by 9:

x + y = 85 -> x = 85 - y.

Debbie worked five hours more than juan during the week, hence:

y = x + 5.

Since x = 85 - y, we replace in the expression:

y = 85 - y + 5.

2y = 90.

y = 45.

Debbie worked 45 hours during the week.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

3 0

2 years ago

If kendal payed $2,500 down and $150 each month for dealer one and at another dealer paid $3,000 down and $125 each month after

maxonik [38]

After 20 months. after 20 months the first dealer will cost 5500 and the second dealer will cost 5500
dealer one pays 3000 in monthly fines and 2500 down and dealer 2 pays 2500 in fines and 300 down

6 0

2 years ago

What multiplies to 16 and adds to negative 12

Romashka-Z-Leto [24]

Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm

we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

0=x^2+12x+16
a=1
b=12
c=16

x= $\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}$
x= $\frac{-12+/- \sqrt{144-64 }}{2}$
x= $\frac{-12+/- \sqrt{80}}{2}$
x= $\frac{-12+/- 4\sqrt{5}}{2}$
x= $\frac{-6+/- 2\sqrt{5}$
x= $\frac{-6+ 2\sqrt{5}$ or $\frac{-6- 2\sqrt{5}$

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0

3 years ago

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Help with these 4 30 points NEED TO BE DONE BEFORE TOMORROW

Vladimir79 [104]

1 is 96 because you must do the inverted T

4 0

3 years ago

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