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3 years ago

Evaluate l-a^2l, given a = 5, b = -3, and c= -2.

Mathematics

2 answers:

mash [69]3 years ago

6 0

THE ANSWER ISSS
25 WHICH IS C

dimulka [17.4K]3 years ago

3 0

I’m sorry bro I wish I knew

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Would 1/5 be greater than 1/3 but less than 2/3

makvit [3.9K]

1/5 = 3/15
1/3 = 5/15
2/3 = 10/15
So no :)

Reason why:
You want to find the common denominator between all three fractions, so all fractions are the same proportions. So in this case, if you multiply 5*3 you get 15, making it the common denominator. Then since you multiplied the 5 in 1/5 by 3 to get 15, and you have to multiply the 3 in 1/3 and 2/3 by 5 to get 15, then you multiply the numerator by the same number.

Sorry I am terrible at explaining things. Hope this helped though!

7 0

3 years ago

Find the value of n if (81)^5/n = 243

zavuch27 [327]

Answer:

N = 14348907

Step-by-step explanation:

81^5 = 3486784401

3486784401/243 = 14348907

Double Check

3486784401 / 14348907=243

So N = 14348907.

3 0

3 years ago

8 = 4 - 2x<br> - 2x +5 = 17<br> 12= - 3 ( x+ 5)

max2010maxim [7]

$8 = 4 - 2x\\8 + 2x = 4\\2x = -4\\x = -2$

$- 2x +5 = 17\\-2x =12\\x = -6$

$12= - 3 ( x+ 5)\\12 = -3x -15\\-3x =27\\x= -9$

5 0

3 years ago

Ivan has 6 times as many blue beads as red beads. he has 49 red and blue beads in all. how many blue beads does Ivan have

salantis [7]

Let

x--------> the number of blue beads

y--------> the number of red beads

we know that

$x+y=49$

$x=49-y$ -------> equation $1$

$x=6y$ ------> equation $2$

equate equation $1$ and equation $2$

$49-y=6y\\ 6y+y=49\\ 7y=49\\\\ y=\frac{49}{7} \\ \\ y=7$

find the value of x

$x=6*7\\ x=42$

therefore

the answer is

Ivan has $42$ $blue beads$

3 0

3 years ago

Read 2 more answers

polynomial function of degree 4 with -1 as a zero of multiplicity 3 and 0 as a zero of multiplicity 1

iren [92.7K]

$\bf \begin{cases}
x=-1\implies &x+1=0\\
x=0\implies &x=0
\end{cases}
\\\\\\
\stackrel{\textit{multiplicity of 3}}{(x+1)^3}~~\stackrel{\textit{multiplicity of 1}}{(x)^1}=\stackrel{original~polynomial}{0}
\\\\\\
(x^3+3x^2+3x+1)(x)=\stackrel{y}{0}\implies x^4+3x^3+3x^2+x=y$

6 0

3 years ago