1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AleksAgata [21]
3 years ago
5

Can you people help me please

Chemistry
1 answer:
vredina [299]3 years ago
5 0
Because they believed that heavenly bodies’ circular motions where caused by their being attached to unseen resolving solid spheres
You might be interested in
To produce energy, nuclear power plants use a process called...
vovangra [49]
I think it’s b but I could be wrong
5 0
2 years ago
Read 2 more answers
Is this chemical equation balanced?
cluponka [151]

Answer:

Yes

Explanation:

5 0
3 years ago
Read 2 more answers
In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
Two types of electro magnetic radiation that you can see with a telescope
agasfer [191]
You tellme i have the same anwser
    botch # bit

6 0
3 years ago
Consider the substances below and predict in which of these substances is hydrogen bonding likely to play an important role in d
kolezko [41]

Explanation:

the otion correct is H2S

6 0
2 years ago
Other questions:
  • Please help!! I think this is true but I really need help.
    12·1 answer
  • I WILL GIVE THE BRAINIEST ANSWER TO THE FIRST PERSON TO ANSWER.TIMED QUIZ!!!ANSWER QUICKLY PLEASE.
    12·2 answers
  • What is the last element in period 4?
    7·1 answer
  • If there are 20.0g of KOH available, how many grams Ca(OH)2 will form?
    13·1 answer
  • H E L P <br> M E H <br> P L E A S E
    9·1 answer
  • How many electrons are there in 2 g of H2
    10·1 answer
  • Which element has a greater ionization energy, rubidium or iodine?
    6·1 answer
  • Propose a synthesis of phenylacetaldehyde from bromobenzene
    14·1 answer
  • GIVING BRAINLIEST!
    15·1 answer
  • A scientist performed an experiment with a mouse where the mouse was moving along a track with a new experimental unscented chee
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!