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Maksim231197 [3]
3 years ago
13

What are they h-bond water acceptors in fentanyl, and is it souluable in water? Explain why or why not.

Chemistry
1 answer:
professor190 [17]3 years ago
7 0

Here we have to get the atom, in the molecule fentanyl, which will behave as a hydrogen (H) bond acceptor from the donor water molecule.

The -O atom in the molecule will behave as the hydrogen bond acceptor from water.

The H-bond always forms between the proton (here water i.e. H₂O) and the proton acceptor atom in a molecule which is essentially is an electronegative element.

In the fentanyl molecule there are two nitrogen (N) atom and one oxygen (O) atom. We know the electronegativity of oxygen is more than the nitrogen. Thus it is expected that the O atom will be H-bond acceptor in the molecule.

The hydrogen bond with water molecule is shown in the figure.

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Answer:

The ratio [A-]/[HA] increase when the pH increase and the ratio decrease when the pH decrease.

Explanation:

Every weak acid or base is at equilibrium with its conjugate base or acid respectively when it is dissolved in water.

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This equilibrium depends on the molecule and it acidic constant (Ka). The Henderson-Hasselbalch equation,

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shows the dependency between the pH of the solution, the pKa and the concentration of the species. If the pH decreases the concentration of protons will increase and the ratio between A- and AH will decrease. Instead, if the pH increases the concentration of protons will decreases and the ratio between A- and AH will increase.

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Explanation:

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A cylinder with a moveable piston contains 0.552 mol of gas and has a volume of 259 mL . Part A What will its volume be if an ad
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