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Maksim231197 [3]
3 years ago
13

What are they h-bond water acceptors in fentanyl, and is it souluable in water? Explain why or why not.

Chemistry
1 answer:
professor190 [17]3 years ago
7 0

Here we have to get the atom, in the molecule fentanyl, which will behave as a hydrogen (H) bond acceptor from the donor water molecule.

The -O atom in the molecule will behave as the hydrogen bond acceptor from water.

The H-bond always forms between the proton (here water i.e. H₂O) and the proton acceptor atom in a molecule which is essentially is an electronegative element.

In the fentanyl molecule there are two nitrogen (N) atom and one oxygen (O) atom. We know the electronegativity of oxygen is more than the nitrogen. Thus it is expected that the O atom will be H-bond acceptor in the molecule.

The hydrogen bond with water molecule is shown in the figure.

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There are two naturally occurring isotopes of copper. 63cu has a mass of 62.9296 amu. 65cu has a mass of 64.9278 amu. determine
SSSSS [86.1K]
1) You need to use the atomic mass of copper.


You can find it in a periodic table. It is 63.546 amu.


2) The atomic mass is the weigthed mass of the different isotopes.


This is, the atomic mass of one element is the atomic mass of each isotope times its corresponding abundance:


=> atomic mass of the element = abundance isotope 1 * atomic mass isotope 1 + abundance isotope 2 *  atomic mass isotope 2 + ....+abundance isotope n * atomic mass isotope n.


3) The statement tells there are two isotopes so the abundance of one is x and the abundance of the other is 1 - x


=> 63.546 amu = x * 62.9296 amu + (1-x)*64.9278


=> 63.546 = 62.9296x + 64.9278 - 64.9278x


=> 64.9278x - 62.9296 = 64.9278 - 63.546


=> 1.9982x = 1.3818


=> x = 1.3818 / 1.9982 = 0.6915 = 69.15%


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Cu-63 69.15%;


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3 years ago
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