What are they h-bond water acceptors in fentanyl, and is it souluable in water? Explain why or why not.

Chemistry

1 answer:

professor190 [17]3 years ago

7 0

Here we have to get the atom, in the molecule fentanyl, which will behave as a hydrogen (H) bond acceptor from the donor water molecule.

The -O atom in the molecule will behave as the hydrogen bond acceptor from water.

The H-bond always forms between the proton (here water i.e. H₂O) and the proton acceptor atom in a molecule which is essentially is an electronegative element.

In the fentanyl molecule there are two nitrogen (N) atom and one oxygen (O) atom. We know the electronegativity of oxygen is more than the nitrogen. Thus it is expected that the O atom will be H-bond acceptor in the molecule.

The hydrogen bond with water molecule is shown in the figure.

You might be interested in

3.75 g of an unknown gas at 59 °C and 1.00 atm is stored in a 1.35-L flask. What is the molar mass of the gas?

MAXImum [283]

You need to find moles of the gas, so you would use the ideal gas law:
PV=nRT
Pressure
Volume
n=moles
R= gas constant
Tenperature in Kelvin
n= PV/RT
(1.00atm)(1.35L)/(.08206)(332K) = 0.050mol
Molar mass is grams per mole, so
(3.75g/.050mol) = 75g/mol

4 0

3 years ago

A sample of element X contains 90% X-35 atoms, 8.0% X-37 atoms, and 2.0% X-38 atoms. The average atomic mass will be closest to

Ne4ueva [31]

To find average atomic mass you multiply the mass of each isotope by its percentage, and then add the values up.

35 * 0.90 + 37 * 0.08 + 38 * 0.02 = 35.22

Average atomic mass closest to 35.22 amu.

6 0

3 years ago

Read 2 more answers

Which water cycle processes might be responsible for helping to clean/ filter the water? Explain.

Leya [2.2K]

to be as exact as i can it is all of them they all work together to make water good.

7 0

3 years ago

What is the mass in grams of 6.12 x 10^20 molecules of caffeine, C8H10N4O2?

baherus [9]

$6,02*10^{23} \ \ \ \ \ \ \rightarrow \ \ \ \ \ 194,2g\\
6,12 * 10^{20} \ \ \ \ \ \ \rightarrow \ \ \ \ \ x\\\\
x=\frac{6,12*10^{20}*194,2g}{6,02*10^{23}}\approx197*10^{-3}g=0,197g$

6 0

3 years ago

30 pts! Sodium and water react according to the following equation. If 31.5g of sodium are added to excess water, how many liter

mihalych1998 [28]

First, calculate the number of moles of sodium present with the given mass,

31.5 g of sodium x (1 mol sodium/ 23 g sodium) = 1.37 mol sodium

It is given in the equation that for every 2mols of sodium, one mol of H2 is produced.

mols of H2 = (1.37 mols sodium)(1 mol H2/ 2 mols sodium)
mols of H2 = 0.685 mols H2

Then, at STP, 1 mol of gas = 22.4 L.

volume of H2 = (0.685 mols H2)(22.4 L / 1 mol)
volume of H2 = 15.34 L

Answer: 15.34 L

3 0

3 years ago