Which sample would have the same number of molecules as 11.2L of He (g) at 273K and 202kPa?
1 answer:
Answer: 11.2 L of at 273K and 202kPa
Explanation:
According to ideal gas equation:
P = pressure of gas = 202 kPa = 1.99 atm ( 1kPa= 0.0098 atm)
V = Volume of gas = 11.2 L
n = number of moles = ?
R = gas constant =
T =temperature =
According to avogadro's law, equal number of moles occupy equal volumes and contain equal number of molecules at same temperature and pressure conditions.
As 11.2 L of at 273K and 202kPa will have same moles as 11.2L of He (g) at 273K and 202kPa, thus they have same number of molecules.
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Answer:
The book sitting on the desk
Explanation:
The gravitational potential energy of an object is the energy possessed by the object due to its position relative to the ground.
It is calculated as:
where
m is the mass of the object
g is the acceleration due to gravity
h is the height of the object with respect to the ground
From the formula, we see that the GPE of an object is directly proportional to the heigth h: so, the higher the location of the object, the larger the GPE.
In this problem, we are comparing a book sitting on a desk and the same book sitting on the floor. In the two situations, the mass of the book is the same; however, in the first case, the value of the height is h, while in the second case, the value of h is lower (because the book is located at a lower height, being on the floor).
Therefore, we can conclude that the first book must have a larger GPE, since it has a larger value of h.