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AVprozaik [17]
2 years ago
8

Find this answer you'll get 25 points 82÷4×(2+3)−9=

Mathematics
1 answer:
butalik [34]2 years ago
5 0

Answer:

82÷4⋅(2+3)−9

Step-by-step explanation:

Write the problem as a mathematical expression.

82÷4⋅(2+3)−9

Simplify each term.

205/2−9

To write

−9

as a fraction with a common denominator, multiply by

2/2

205/2−9⋅2/2

Combine

−9 and 22.

205/2+ −9⋅2/2

Combine the numerators over the common denominator.

205−9⋅2/2

Simplify the numerator.

187/2

The result can be shown in multiple forms.

Exact Form:

187/2

Decimal Form:

93.5

Mixed Number Form:

93 1/2

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Triangle ABC has been reflected over the y- axis to create triangle A’B’C’. Which of the following statements is true ? B’C’ = 2
Klio2033 [76]

Answer:

B'C' = 2

Step-by-step explanation:

Just took the FLVS test and it was correct

6 0
3 years ago
What is the volume of the oblique cone? Round to the
Black_prince [1.1K]

Answer:

142.4 Cubic units

Step-by-step explanation:

V=1/3pir^2h

V=1/3(pi)(4^2)(8.5)

V=142.418866963

5 0
3 years ago
Read 2 more answers
What is the distance between Point A: (-4, -3) and Point B (1, 4) ?
Sholpan [36]

Answer:

sq rt 74 which is approx 8.6

Step-by-step explanation:

use distance formula

6 0
2 years ago
Look at the graph shown below:
ElenaW [278]
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 4}})\quad 
%   (c,d)
&({{ -4}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=0\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}

once you get the slope and solve for "y", that'd be the equation of the line.
7 0
3 years ago
Your friend claims that if a line has a slope less than 1, then any line perpendicular to it must have a positive slope. Is your
mezya [45]

Answer:

The friend's claim is not correct

Step-by-step explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal yo -1)

Example

A given line has a slope of m_1=1/2  ---> (is less than 1)

the slope of the line perpendicular to the given line is equal to

m_1*m_2=-1

substitute

(1/2)*m_2=-1

m_2=-2

so

the perpendicular line don't have a positive slope

therefore

The friend's claim is not correct

5 0
3 years ago
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