Answer:
Hz
Explanation:
In alternating current (AC) circuits, voltage (V) oscillates in a sine wave pattern and has a general equation as a function of time (t) as follows;
V(t) = V sin (ωt + Ф) -----------------(i)
Where;
V = amplitude value of the voltage
ω = angular frequency = 2 π f [f = cyclic frequency or simply, frequency]
Ф = phase difference between voltage and current.
<u><em>Now,</em></u>
From the question,
V(t) = 230 sin (100t) ---------------(ii)
<em><u>By comparing equations (i) and (ii) the following holds;</u></em>
V = 230
ω = 100
Ф = 0
<em><u>But;</u></em>
ω = 2 π f = 100
2 π f = 100 [divide both sides by 2]
π f = 50
f = Hz
Therefore, the frequency of the voltage is Hz
Floodplains are landscapes shaped by running water. As streams and their larger forms, rivers, flow across the surface of land, they transport eroded rock and other material. (Erosion is the gradual wearing away of Earth surfaces through the action of wind and water.) At points along that journey, when their flow slows, the material they carry is dropped to create what are termed depositional landforms. Among these landforms are deltas and floodplains.
Read more: http://www.scienceclarified.com/landforms/Faults-to-Mountains/Floodplain.html#ixzz7BNHuUb00
Answer:
(D) 3
Explanation:
The angular momentum is given by:
Thus, the magnitude of the angular momenta of both solar systems are given by:
where we have taken that both systems has the same radius.
By taking into account that T1=3T2, we have
but L1=L2=L:
Hence, the answer is (D) 3
HOPE THIS HELPS!!
Answer:
3.75 m/s
Explanation:
Given that a bumblebee is flying to the right when a breeze causes the bee to slow down with a constant leftward acceleration of magnitude 0.50 m/s^2. After 2.0 s the bee is moving to the right with a speed of 2.75 m/ s
What was the velocity of the bumblebee right before the breeze?
Since the breeze blows with the acceleration of 0.5 m/s^2 for 2 seconds, we can calculate the magnitude of the velocity at which it moves.
Acceleration = velocity/ time
Substitute the acceleration and time into the formula
0.5 = V/2
Cross multiply
V = 2 × 0.5
V = 1 m/s
The bumblebee is travelling right ward while the wind travels leftward.
The relative velocity = 2.75 m/s
Let the bumblebee speed = Vb
While the wind = VW
Vb - Vw = 2.75
Substitute the wind speed into the formula
Vb - 1 = 2.75
Vb = 2.75 + 1
Vb = 3.75 m/s
Therefore, the velocity of the bumblebee right before the breeze is 3.75 m/s
As the box compresses the spring, the spring performs
-1/2 (85 N/m) (0.065 m)² ≈ -0.18 J
of work on the box. By the work energy theorem, the total work performed on the box (which is done only by the spring since there's no friction) is equal to the change in the box's kinetic energy. At full compression, the box has zero instantaneous speed, so
<em>W</em> = ∆<em>K</em> ==> -0.18 J = 0 - 1/2 (2.5 kg) <em>v</em> ²
where <em>v</em> is the box's speed when it first comes into contact with the spring. Solve for <em>v</em> :
<em>v</em> ² ≈ 0.14 m²/s² ==> <em>v</em> ≈ 0.38 m/s
