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kirill115 [55]
3 years ago
13

A ray of monochromatic light is incident on a plane mirror at and angle of 30. The angle of reflection for the light is

Physics
1 answer:
Juliette [100K]3 years ago
3 0

Answer:

30 degrees

Explanation: reflection, same angle

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An athlete needs to lose weight and decides to do it by "pumping iron." (a) How many times must an 60.0 kg weight be lifted a di
Dennis_Churaev [7]

Answer:

a) 37171

b) 20650.5 sec

Explanation:

m = mass of the weight being lifted = 60.0 kg

d = distance by which the weight is lifted = 0.670 m

E = Energy available to burn = 1 lb = 3500 kcal = 3500 x 4184 J

g = acceleration due to gravity = 9.8 m/s²

n = number of times the weight is lifted

Energy available to burn is given as

E = n m g d

3500 x 4184 = n (60) (9.8) (0.670)

n = 37171

b)

T = time period for each lift up = 1.80 s

t = total time taken

Total time taken is given as

t = \frac{n}{T}

t = \frac{37171}{1.80}

t = 20650.5 sec

8 0
3 years ago
If the temperature of the metal oxide and water solution is increased,this would most likely..
kiruha [24]
Chemical Reaction between metal oxide and water solution
7 0
3 years ago
2)It is known that the connecting rodS exerts on the crankBCa 2.5-kN force directed down andto the left along the centerline ofA
11111nata11111 [884]

Answer:

M_c = 100.8 Nm

Explanation:

Given:

F_a = 2.5 KN

Find:

Determine the moment of this force about C for the two cases shown.

Solution:

- Draw horizontal and vertical vectors at point A.

- Take moments about point C as follows:

                        M_c = F_a*( 42 / 150 ) *144

                        M_c = 2.5*( 42 / 150 ) *144

                        M_c = 100.8 Nm

- We see that the vertical component of force at point A passes through C.

Hence, its moment about C is zero.

5 0
4 years ago
• (-/1 Points) DETAILS OSCOLPHYS2016 9.5.WA.040.
Tanya [424]

The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

<h3>Force exerted outside the wheel</h3>

The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.

∑τ = 0

  • Let the distance traveled by the load = 1.5 m
  • Let the radius of the wheel or position of the force = 0.45 m

∑τ = R(mg) - r(F)

rF = R(mg)

0.45F = 1.5(21,200 x 9.8)

F = 6.925 x 10⁵ N.

Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

Learn more about angular momentum here: brainly.com/question/7538238

6 0
3 years ago
When gametes combine to form a zygote, the chromosomes number of the zygote is now referred to as
Serga [27]

the answer to the complicated question is a diploid

6 0
4 years ago
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