HELP PLZ ASAPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

The image of a parabolic lens is traced onto a graph. The function f(x) = (x + 8)(x – 4) represents the image. At which points d

Anna71 [15]

Answer:

$\large \boxed{\sf \ \ \ (-8,0) \ \text{ and } \ (4,0) \ \ \ }$

Step-by-step explanation:

Hello,

from the expression of f(x) we can say that there are two zeroes, -8 with a multiplicity of 1 and 4 with a multiplicity of 1.

So the image of the parabolic lens crosses the x-axis at two points:

(-8,0)

and

(4,0)

For information, I attached the graph of the function.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago

The equation for this linear function is h= -100t + 4000. Determine the t-intercept. What is its significance in this situation?

natima [27]

H= -100t + 4000
To find the t-intercept ⇒⇒⇒ ∴ h = 0
-100 t + 4000 = 0
∴ t = 4000/100 = 40

The correct choice is (c)

c. (40, 0); The jet lands in 40 seconds.

5 0

3 years ago

HELPP! Calculate S22 for the arithmetic sequence in which a12=2.4 and the common difference is d=3.4

Sonbull [250]

Answer:

S22 for the arithmetic sequence is:

First option: 15.4

Step-by-step explanation:

a12=2.4

d=3.4

S22=?

Sn=(a1+an)n/2

n=22

S22=(a1+a22)22/2

S22=(a1+a22)11

ak=aj+(k-j)d

a12=a1+(12-1)d

2.4=a1+11(3.4)

2.4=a1+37.4

Solving for a1: Subtracting 37.4 both sides of the equation:

2.4-37.4=a1+37.4-37.4

Subtracting:

-35=a1

a1=-35

a22=a12+(22-12)d

a22=2.4+10(3.4)

a22=2.4+34

a22=36.4

S22=(a1+a22)11

S22=(-35+36.4)11

S22=(1.4)11

S22=15.4

3 0

3 years ago

Math help asap 12,14,16,18,22 show work help asap assig 4

svetoff [14.1K]

Answer: see below

Step-by-step explanation:

12) 2(x + 4) = 8

÷2 ÷2

x + 4 = 4

-4 -4

$\large\boxed{x=0}$

14) 4w - 2(1 - w) = -38

4w -2 + 2w = -38

(4w + 2w) - 2 = -38

6w - 2 = -38

+2 +2

6w = -36

÷6 ÷6

$\large\boxed{w=6}$

16) 10(1 - 2y) = -5(2y - 1)

10 - 20y = -10y + 5

+20y +20y

10 = 10y + 5

-5 -5

5 = 10y

÷10 ÷10

$\large\boxed{\dfrac{1}{2}=y}$

$18)\quad s=\dfrac{1}{2}gt^2\\\\\\.\qquad (2)s=(2)\dfrac{1}{2}gt^2\quad \rightarrow \quad 2s=gt^2\\\\\\.\qquad \dfrac{2s}{t^2}=\dfrac{gt^2}{t^2}\qquad \rightarrow \qquad\large\boxed{\dfrac{2s}{t^2}=g}$