The answer would be slowly
Answer:
-2040 m/s²
Explanation:
Taking toward the wall to be positive, the initial velocity is 10.1 m/s and the final velocity is -8.3426 m/s.
Average acceleration is the change in velocity over change in time.
a = Δv / Δt
a = (-8.3426 m/s − 10.1 m/s) / 0.00905 s
a = -2040 m/s²
Answer:
Option C is correct.
The component of acceleration perpendicular to an object’s velocity tells us How the object’s direction changes.
Explanation:
This acceleration is called radial/tangential acceleration. It is the reason why a body moving in circular motion with constant velocity can be said to also be accelerating because its direction is continuously changing. The acceleration is usually directed towards the centre of the circular motion of the body or trying to throw the body off its circular motion path.
Given that,
Height =1.5 m
Angle = 45°
We need to find the greater speed of the ball
Using conservation of energy
Here, initial velocity and final potential energy is zero.
Put the value into the formula
Hence, the greater speed of the ball is 5.42 m/s.
Answer:
The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s is 18 m/s
Explanation:
Given that the mass of the dog = 5.0 kg
The mass of the pig = 30 kg
The speed with which the pig is walking = 3.0 m/s
We have that linear momentum = Mass × Velocity
Therefore, the momentum of the pig, m₁ = 30 kg × 3.0 m/s = 90 kg·m/s
m₁ = 90 kg·m/s
The momentum of the dog m₂ = Mass of the dog × Velocity of the dog
Given that m₁ is to be equal to m₂, we have;
m₁ = 90 kg·m/s = m₂ = Mass of the dog × Velocity of the dog
90 kg·m/s = m₂ = 5.0 kg × Velocity of the dog
m₂ = 5.0 kg × Velocity of the dog = 90 kg·m/s
5.0 kg × Velocity of the dog = 90 kg·m/s
Velocity of the dog = 90 kg·m/s/(5.0 kg) = 18 m/s
The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s = 18 m/s.
