An intrusion is any body of intrusive igneous rock, formed from magma that cools and solidifies within the crust of the planet. In contrast, an extrusion consists of extrusive rock, formed above the surface of the crust.
Answer:
The average temperature of the sea surface is about 20° C (68° F), but it ranges from more than 30° C (86° F) in warm tropical regions to less than 0°C at high latitudes. In most of the ocean, the water becomes colder with increasing depth
Answer:

Explanation:
The limiting reactant is the reactant that gives the smaller amount of product.
Assemble all the data in one place, with molar masses above the formulas and masses below them.
M_r: 39.10 80.41 2.016
2K + 2HBr ⟶ 2KBr + H₂
m/g: 5.5 4.04
a) Limiting reactant
(i) Calculate the moles of each reactant

(ii) Calculate the moles of H₂ we can obtain from each reactant.
From K:
The molar ratio of H₂:K is 1:2.

From HBr:
The molar ratio of H₂:HBr is 3:2.

(iii) Identify the limiting reactant
HBr is the limiting reactant because it gives the smaller amount of NH₃.
b) Excess reactant
The excess reactant is K.
c) Mass of H₂

Answer:
Kp is 2.98 (option c.)
Explanation:
The decomposition is:
NH₄NO₃(s) → N₂O(g) + 2H₂O(g)
Total pressure at equilibrium is 2.72 bar so, in order to determine Kp we need the partial pressure and we only have total pressure.
According to stoichiometry, nitrogen oxide increase by 1, the partial pressure and water vapor, by 2.
Total pressure is: Partial pressure N₂O + Partial pressure H₂O
2.72 bar = X + 2X → X = 2.72 bar / 3 = 0.91 bar
Partial pressure N₂O = 0.91 bar
Partial pressure H₂O = 1.81 bar
We make the expression for Kp = Partial pressure N₂O . (P. pressure H₂O)²
Kp = 0.91 . 1.81² = 2.98
We do not consider the ammonium nitrate, because it is solid