Explanation:
First, let's rewrite the equation here:
4 NH3 + 6 NO -> 5 N2 + 6 H2O.
The equation tells us that 6 moles of NO produces 5 moles of N2.
But the question wants us to find the quantity in grams of NO required if we have 121 g of N2.
1. So first, let's transform 121 g of N2 into moles, using its molar mass (28 g/mol) and the following formula: moles = mass/molar mass
2. Then, we use the equation ratio between NO and N2: 6:5.
3. Then we transform the result into grams of NO, using its molar mass (30.01 g/mol) and the following formula: mass = moles*molar mass
1. moles = 121/28
moles = 4.3 moles of N2
2. 6 moles of NO --- 5 moles of N2
x moles of NO --- 4.3 moles of N2
5x = 4.3*6
x = 25.9/5
x = 5.2 moles of NO
3. mass = 5.2*30.01
mass = 155.6 g
Answer: It will require 155.6 g of NO.
Answer is 54 °C.
<em>Explanation;</em>
We can simply use heat equation
Q = mcΔT
Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Let's assume that the initial temperature is T.
Q = 5.53 × 10⁵ J
m = 2850 g
c = 4.186 J/g °C
ΔT = (100 - T) °C <em>Since the water is boiling, the final temperature is 100 °C.</em>
By applying the equation,
5.53 × 10⁵ J = 2850 g x 4.186 J/g °C x (100 - T) °C
(100 - T) °C = 5.53 × 10⁵ J / (2850 g x 4.186 J/g °C )
(100 - T) °C = 46.35 °C
T = 100 - 46.35 C = 53.65 °C
≈ 54 °C
Answer:
radio waves are the sound waves that are produces by a radio
Explanation:
Answer:
0.5m/s2
Explanation:
Data obtained from the question include:
u (initial velocity) = 0m/s
v (final velocity) = 30m/s
t (time) = 1min = 60secs
a (Acceleration) =?
a = v — u/t
a = 30—0 / 60
a = 30/60
a = 0.5m/s2
