Solid calcium hydroxide is dissolved in water until the pH of the solution is 10.44. Determine the concentration of the calcium
1 answer:
Answer:
1.38x10⁻⁴ M
Explanation:
First, we <u>calculate the pOH of the solution</u>, using the <em>given pH</em>:
- pOH = 14 - pH
- pOH = 14 - 10.44
- pOH = 3.56
Now we <u>calculate the concentration of OH⁻</u>, using<em> the pOH</em>:
- pOH = -log[OH⁻]
- [OH⁻] =
= 2.75x10⁻⁴ M
Following the reaction Ca(OH)₂ → Ca⁺² + 2OH⁻, we divide [OH⁻] by 2 to calculate [Ca(OH)₂]:
- [Ca(OH)₂] = 2.75x10⁻⁴ M / 2
- [Ca(OH)₂] = 1.38x10⁻⁴ M
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Answer:
A beaker
Step-by-step explanation:
Specifically, I would use a 250 mL graduated beaker.
A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.
You don't need precisely 100 mL solution.
If the beaker is graduated, you can easily measure 100 mL of the stock solution.
Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).
