The reaction below has an equilibrium constant kp=2.2×106 at 298 k. 2cof2(g)⇌co2(g)+cf4(g) calculate kp for the reaction below.
2 answers:
<h3>Kp = 1.483 . 10³</h3><h3>Further explanation</h3>
The equilibrium constant is the ratio of concentration or pressure between the results of the reaction / product and the reactant with each reaction coefficient raised
The equilibrium constant is based on the concentration (Kc) in a reaction
pA + qB -----> mC + nD
While the equilibrium constant is based on partial pressure
The value of Kp and Kc can be linked to the formula '
R = gas constant = 0.0821 L.atm / mol.K
=n = number of product coefficients-number of reactant coefficients
There are rules in determining the Kp value for the related reaction
- 1. If the reaction equation is reversed, the value of Kp is also reversed
- 2. if the reaction coefficient is divided by a factor n, then the new Kp value is the square root of n from the old Kp
- 3. if the reaction coefficient is multiplied by the factor n, then the new Kp value is the power of n from the old Kp
2COF₂ (g) ⇌CO₂(g) + CF₄ (g) Kp = 2.2 × 10⁶ at 298 K(reaction 1)
For the reaction 2, the reaction coefficient is divided by 2, so the new Kp value :
an equilibrium constant brainly.com/question/9173805
Calculate the value of the equilibrium constant, Kc
Concentration of hi at equilibrium
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Norfenefrine (C₈H₁₁NO₂).
<h3>Further explanation</h3>We will solve a case related to one of the colligative properties, namely freezing point depression.
The freezing point of the solution is the temperature at which the solution begins to freeze. The difference between the freezing point of the solvent and the freezing point of the solution is called freezing point depression.
<u>Given:</u>
A mysterious white powder could be,
- powdered sugar (C₁₂H₂₂O₁₁) with a molar mass of 342.30 g/moles,
- cocaine (C₁₇H₂₁NO₄) with a molar mass of 303.35 g/moles,
- codeine (C₁₈H₂₁NO₃) with a molar mass of 299.36 g/moles,
- norfenefrine (C₈H₁₁NO₂) with a molar mass of 153.18 g/moles, or
- fructose (C₆H₁₂O₆) with a molar mass of 180.16 g/moles.
When 82 mg of the powder is dissolved in 1.50 mL of ethanol (density = 0.789 g/cm³, normal freezing point −114.6°C, Kf = 1.99°C/m), the freezing point is lowered to −115.5°C.
<u>Question: </u>What is the identity of the white powder?
<u>The Process:</u>
Let us identify the solute, the solvent, initial, and final temperatures.
- The solute = the powder
- The solvent = ethanol
- The freezing point of the solvent = −114.6°C
- The freezing point of the solution = −115.5°C
Prepare masses of solutes and solvents.
- Mass of solute = 82 mg = 0.082 g
- Mass of solvent = density x volume, i.e.,
We must prepare the solvent mass unit in kg because the unit of molality is the mole of the solute divided by the mass of the solvent in kg.
The molality formula is as follows:
Now we combine it with the formula of freezing point depression.
It is clear that we will determine the molar mass of the solute (denoted by Mr).
We enter all data into the formula.
We get
These results are very close to the molar mass of norfenefrine which is 153.18 g/mol. Thus the white powder is norfenefrine.
<h3>Learn more</h3>- The molality and mole fraction of water brainly.com/question/10861444
- About the mass and density of ethylene glycol as an antifreeze brainly.com/question/4053884
- About the solution as a homogeneous mixture brainly.com/question/637791
Keywords: a mysterious white powder, sugar, cocaine, codeine, norfenefrine, fructose, the solute, the solvent, dissolved, ethanol, normal freezing point, the freezing point depression, the identity
