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SashulF [63]
4 years ago
14

The question is in the picture below.

Chemistry
1 answer:
pantera1 [17]4 years ago
4 0
The correct option is A.
An oxidation reaction is one in which a substance gives away electrons and becomes oxidized. In the equation given above, the chlorate ion undergoes oxidation reaction and gives away two chlorine ion.
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Sedaia [141]
The earths moon is most like going to differ in size or even color
6 0
4 years ago
Read 2 more answers
Help pls ill give extra points
r-ruslan [8.4K]

Explanation:

im sorry but it depends on what the diagram looks like for the problem

3 0
3 years ago
Which description applies to a physical property? Choose the correct answer
choli [55]

Answer:

the third one, measured or observed without changing the identity and composition of matter. because physical property does not under go any change but can be put back.

6 0
3 years ago
When mixed, solutions of silver nitrate, AgNO3, and sodium sulfate, Na2SO4, form a precipitate of silver sulfate, Ag2SO4. The ba
Maslowich

Answer:

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

Explanation:

The general schemefor a reaction is given as;

Reactants --> Products

In this question, the reactants are AgNO3 and Na2SO4. The product is Ag2SO4.

The equation is given as;

AgNO3 + Na2SO4 --> Ag2SO4

The other poduct formed in this reaction is NaNO3.

The full reaction is given as;

AgNO3 + Na2SO4 --> Ag2SO4 + NaNO3

The above reaction is not balanced because there are unequal number of atoms of the elements on both sides of the reaction.

The balanced equation is given as;

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

In this equation, there are equal number of moles of the atoms on both sides.

3 0
3 years ago
A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal
Oxana [17]

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 16.59 g

Volume (v) =  5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

Substitute the values into the formula:

​p = \frac{16.59 g}{5.81 mL} \\   = 2.8554 g/mL

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

5 0
2 years ago
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