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SashulF [63]
3 years ago
14

The question is in the picture below.

Chemistry
1 answer:
pantera1 [17]3 years ago
4 0
The correct option is A.
An oxidation reaction is one in which a substance gives away electrons and becomes oxidized. In the equation given above, the chlorate ion undergoes oxidation reaction and gives away two chlorine ion.
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A gas occupies a volume of 650.0 mL when the pressure is 3.50 atm. What will the new volume be if the pressure is reduced to 1.6
Gemiola [76]

The new volume will be 1379 mL.

Explanation:

As per Boyle's law, the product of initial volume and initial pressure of any gas molecule is equal to the product of final volume and final pressure of those molecules.

So here the initial volume is 650 ml and the initial pressure is 3.50 atm. As the temperature is said to be constant, then this system will be obeying Boyle's law. So, the final pressure is given as 1.65 atm. As there is a reduction in the pressure, the volume of the gas is tend to get expanded.

P_{1} V_{1} = P_{2} V_{2}

So, (650*10^{-3}*3.50)=(1.65*V_{2})

V_{2} = \frac{650*10^{-3}*3.50}{1.65} = 1379 mL

So, the new volume of the gas on reduction in pressure is 1379 mL.

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3 years ago
Dr. Winters decides not to tell the people in his experiment about the potential risks. He
anzhelika [568]

Answer: sorry I cant help you I need the same answer

Explanation:

5 0
3 years ago
Why is NaNO3 a homogenous mixture in terms of particle arrangement/composition?
Fed [463]
<span> A homogeneous mixture is composed of a single visible phase while a heterogeneous mixture has two or more</span>
8 0
3 years ago
3. Calculate the answers to the appropriate number of significant figures. e) 43.678 x 64.1 = f) 1.678/0.42 =
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For the reaction CO2(g) + H2(g)CO(g) + H20(g)
Studentka2010 [4]

Answer:

The ΔG° is 29 kJ and the reaction is favored towards reactant.

Explanation:

Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,  

ΔG° = ΔH°rxn - TΔS°rxn

= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K

= 41.2 kJ - 12.2 kJ

= 29 kJ

As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.  

5 0
3 years ago
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