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jek_recluse [69]
3 years ago
13

For the reaction CO2(g) + H2(g)CO(g) + H20(g)

Chemistry
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

The ΔG° is 29 kJ and the reaction is favored towards reactant.

Explanation:

Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,  

ΔG° = ΔH°rxn - TΔS°rxn

= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K

= 41.2 kJ - 12.2 kJ

= 29 kJ

As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.  

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A 0.105 L sample of an unknown HNO 3 solution required 35.7 mL of 0.250 M Ba ( OH ) 2 for complete neutralization. What is the c
oksano4ka [1.4K]

Answer: 0.17M

Explanation:

The equation for the reaction is :

2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O

From the balanced equation, we obtain :

nA = mole of acid = 2

nB = mole of the base = 1

From the question, we obtain:

Va = Vol. Of acid = 0.105L

Ma = conc. Of acid =?

Vb = Vol of base = 35.7 mL = 0.0357L

Mb = conc. of base = 0.25M.

We solve for the conc. of the acid using:

MaVa / Mb Vb = nA / nB

(Ma x 0.105) / (0.25x0.0357) = 2

Cross multiply to express in linear form. We have:

Ma x 0.105 = 0.25 x 0.0357 x 2

Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

Ma = 0.17M

Therefore the concentration of the acid(HNO3) is 0.17M

3 0
3 years ago
Nvmmmmmmmmmmmmmmmmmmmmmmmmm lol
Vlad1618 [11]

Answer:

coooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooool lol

Explanation:

7 0
3 years ago
Read 2 more answers
Please help with this question​
Anastasy [175]

Answer:

215 amu

Explanation:

In the reactants:

There is 1 iron atom, 3 chlorine atoms, 6 hydrogen atoms and 3 oxygen atoms:

  • Fe: 56 × 1 = 56
  • Cl: 35 × 3 = 105
  • H: 1 × 6 = 6
  • O: 16 × 3 = 48

56 + 105 + 6 + 48 = 215 amu

Hope this helps!

8 0
2 years ago
What was technicalagy like in the past
V125BC [204]
Most of it was analog
8 0
3 years ago
Read 2 more answers
How many grams are there in 1.1 x 1027 molecules of water (H2O)?
Nezavi [6.7K]

Answer:

C) 3.3 x 104 grams

Explanation:

1 mole of water contains 6.02 × 10^23 atoms

1.1 × 10^27 atoms will contain;

1.1 × 10^27 ÷ 6.02 × 10^23

= 0.1827 × 10^( 27 - 23)

= 0.1827 × 10^(4)

= 1.827 × 10³ moles of water.

To convert mole to mass in grams, we use the formula;

mole (n) = mass (m) ÷ molar mass (MM)

Molar mas of water (H2O) = 1(2) of H + 16 of O = 18g/mol

mole = mass/molar mass

1.827 × 10³ = mass / 18

mass = 1.827 × 10³ × 18

mass = 32.886 × 10³

mass = 3.286 × 10⁴

mass = 3.3 × 10⁴ grams

6 0
3 years ago
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