Answer: 150 kPa
Explanation:
Given that,
Original volume of gas V1 = 30L
Original pressure of gas P1 = 105 kPa
New pressure of gas P2 = ?
New volume of gas V2 = 21L
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
105 kPa x 30L = P2 x 21L
3150 kPa L = P2 x 21L
P2 = 3150 kPa L / 21 L
P2 = 150 kPa
Thus, 150 kPa of pressure is required to compress the gas
MgCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MgCl2 that dissolves.
MgCl2(s) --> Mg+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.098 mol MgCl2/1L × 2 mol Cl⁻ / 1 mol MgCl2 = 0.20 M
The answer to this question is [Cl⁻] = 0.20 M
Answer:
The answer to your question is Pressure = 5 atm
Explanation:
Data
Volume 1 = V1 = 0.5 l
Pressure 1 = P1 = 1 atm
Volume 2 = V2 = 0.1 l
Pressure 2 = P2 = x
Formula
To solve this problem use the Boyle's equation
V1P1 = V2P2
Solve for P2
P2 = V1P1/V2
Substitution
P2 = (0.5 x 1) / 0.1
Simplification
P2 = 0.5/0.1
Result
P2 = 5 atm
