Question

A gas occupies a volume of 650.0 mL when the pressure is 3.50 atm. What will the new volume be if the pressure is reduced to 1.65 atm and the temperature remains constant.

Answer 1

The new volume will be 1379 mL.

Explanation:

As per Boyle's law, the product of initial volume and initial pressure of any gas molecule is equal to the product of final volume and final pressure of those molecules.

So here the initial volume is 650 ml and the initial pressure is 3.50 atm. As the temperature is said to be constant, then this system will be obeying Boyle's law. So, the final pressure is given as 1.65 atm. As there is a reduction in the pressure, the volume of the gas is tend to get expanded.

$P_{1} V_{1} = P_{2} V_{2}$

So, $(650*10^{-3}*3.50)=(1.65*V_{2})$

$V_{2} = \frac{650*10^{-3}*3.50}{1.65} = 1379 mL$

So, the new volume of the gas on reduction in pressure is 1379 mL.