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Sliva [168]
3 years ago
8

A student uses 0.0821 L• atm/mol • K as the value of the gas constant. What is most likely true about the variables in the ideal

gas law?
Chemistry
1 answer:
Nikitich [7]3 years ago
3 0

Answer:

The Variables in the ideal gas law are taking into account the behave of a gas in ideal conditions. Ideal conditions are established to make all calculations easier than use the real gas equation.

Explanation:

If I have 0,082 L*atm/mol*K as ideal constant is because the units and values  that I am using are the following:

22.4L, 1mol , 273,15K, 1 atm

Then in the equation: PV=nRT,    R=PV/nT   =  1atm*22.4L/1mol*273,25K= 0,0821 L• atm/mol • K

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What I know about the Alveoli and Gas exchange
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Explanation:

What happens during gas exchange in the alveoli?

These are called alveoli. They inflate when a person inhales and deflate when a person exhales. During gas exchange oxygen moves from the lungs to the bloodstream. At the same time carbon dioxide passes from the blood to the lungs.

What is the role of alveoli in gas exchange?

The alveoli are where the lungs and the blood exchange oxygen and carbon dioxide during the process of breathing in and breathing out. Oxygen breathed in from the air passes through the alveoli and into the blood and travels to the tissues throughout the body.

7 0
2 years ago
Help plssss <br><br> The question is in the picture above
Paul [167]

Answer:

The answer is : A

8 0
3 years ago
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What is the meaning of the term polar as applied to chemical bonding?
kicyunya [14]
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3 years ago
Which one of the following items does NOT characterize a reducing agent? a. A reducing agent loses electrons. b. A reducing agen
Ad libitum [116K]

Answer: D

Explanation:

A reducing agent is a species that reduces other compounds, and is thereby oxidized. The whole compound becomes the reducing agent. In other words, of a compound is oxidized, then they are the reducing agent. On the other hand, if the compound is reduced, it is an ozidizing agent.

Since we have established that a reducing agent is the compound being oxidized, we know that A is not our answer. An oxidized compound is losing electrons. Choice A states exactly this.

For B, this is true as we have established this already.

C is also correct. Since a reducing agent loses electrons, it becomes more positive. This makes the oxidation number increase.

D would be our correct answer. It is actually a good oxidizing agent is a metal in a high oxidation state, such as Mn⁷⁺.

4 0
3 years ago
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QveST [7]

Explanation :

As we know that Mendeleev arranged the elements in horizontal rows and vertical columns of a table in order of their increasing relative atomic weights.

He placed the elements with similar nature in the same group.

According to the question, the atomic weight of iodine is less than the atomic weight of tellurium. So according to this, iodine should be placed before tellurium in Mendeleev's tables. But Mendeleev placed iodine after tellurium in his original periodic table.

However, iodine has similar chemical properties to chlorine and bromine. So, in order to make iodine queue up with chlorine and bromine in his periodic table, Mendeleev exchanged the positions of iodine and tellurium.

As we know that the positions of iodine and tellurium were reversed in Mendeleev's table because iodine has one naturally occurring isotope that is iodine-127  and tellurium isotopes are tellurium-128 and tellurium-130.

Due to high relative abundance of tellurium isotopes gives tellurium the greater relative atomic mass.

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