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NNADVOKAT [17]
3 years ago
11

How can historical design elements be added to modern building plans?

Engineering
2 answers:
satela [25.4K]3 years ago
5 0

Answer:

is it to late now

Explanation:

zvonat [6]3 years ago
5 0

Answer:

Hydraulic systems

Explanation:

JUST DID A QUIZ WITH IT

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What is the magnitude of the maximum stress that exist at the tip of an internal crack having a radius of curvature of 1.9 x 10-
Hitman42 [59]

Answer:

2800 [MPa]

Explanation:

In fracture mechanics, whenever a crack has the shape of a hole, and the stress is perpendicular to the orientation of such, we can use a simple formula to calculate the maximum stress at the crack tip

\sigma_{m} = 2 \sigma_{p} (\frac{l_{c}}{r_{c}})^{0.5}

Where \sigma_{m} is the magnitude of he maximum stress at the tip of the crack, \sigma_{p} is the magnitude of the tensile stress, l_{c} is 1/2 the length of the internal crack, and r_{c} is the radius of curvature of the crack.

We have:

r_{c}=1.9*10^{-4} [mm]

l_{c}=3.8*10^{-2} [mm]

\sigma_{c}=140 [MPa]

We replace:

\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}

We get:

\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}=2800 [MPa]

5 0
3 years ago
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