Answer:
0.77978
Explanation:
This is a Poisson distribution problem
Poisson distribution formula is given as
P(X = x) = (e^-λ)(λˣ)/x!
λ = mean = 10 tankers per day
x = variable whose probability is required
The probability that more than 7 tankers arrives in a certain day = 1 - (Probability that 7 or less tankers arrive in a certain day)
P(X > 7) = 1 - P(X ≤ 7)
P(X ≤ x) = Σ (e^-λ)(λˣ)/x! (Summation From 0 to x)
P(X ≤ 7) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5) + + P(X=6) + P(X=7) + P(X=8)
Computing this,
P(X≤7) = 0.22022
P(X > 7 ) = 1 - P(X≤7) = 1 - 0.22022 = 0.77978
Answer:
Detailed solution is attached below in three simple steps the problem is solved.
Answer:
69.23VA
Explanation:
![Z=R//Z_{c}=\left ( \frac{1}{R}+\frac{1}{Z_{c}} \right )^{-1}\\ R=1000\Omega\\ X_{c}=1500\Omega\\ Z=R//Z_{c}=\left ( \frac{1}{1000}+\frac{1}{-j1500} \right )^{-1}=832,05\angle-33,69\Omega](https://tex.z-dn.net/?f=Z%3DR%2F%2FZ_%7Bc%7D%3D%5Cleft%20%28%20%5Cfrac%7B1%7D%7BR%7D%2B%5Cfrac%7B1%7D%7BZ_%7Bc%7D%7D%20%5Cright%20%29%5E%7B-1%7D%5C%5C%20R%3D1000%5COmega%5C%5C%20X_%7Bc%7D%3D1500%5COmega%5C%5C%20Z%3DR%2F%2FZ_%7Bc%7D%3D%5Cleft%20%28%20%5Cfrac%7B1%7D%7B1000%7D%2B%5Cfrac%7B1%7D%7B-j1500%7D%20%5Cright%20%29%5E%7B-1%7D%3D832%2C05%5Cangle-33%2C69%5COmega)
Like is an parallel circuit, we can calculate across the voltage and impedance
![S=V.I=\frac{V^2}{Z} \\ S=\frac{240^2}{832,05}\LARGE S=69.23VA](https://tex.z-dn.net/?f=S%3DV.I%3D%5Cfrac%7BV%5E2%7D%7BZ%7D%20%5C%5C%20S%3D%5Cfrac%7B240%5E2%7D%7B832%2C05%7D%5CLARGE%20S%3D69.23VA)
Answer:
The drying time is calculated as shown
Explanation:
Data:
Let the moisture content be = 0.6
the free moisture content be = 0.08
total moisture of the clay = 0.64
total drying time for the period = 8 hrs
then if the final dry and wet masses are calculated, it follows that
t = (X0+ Xc)/Rc) + (Xc/Rc)* ln (Xc/X)
= 31.3 min.