Answer:
There is about 4,164/4,165 chances of not getting getting a four of a kind. So, it is extremely unlikely or even borderline impossible in that situation to get a four of a kind.
<u>But in the long run, it can be increased only if you keep drawing. So, the awnser would have to be. D </u>
Step-by-step explanation:
A. It does mean that if you are dealt 4165 five‑card poker hands, one will be four‑of‑a‑kind.
B. It does not mean that all will be four‑of‑a‑kind. The probability is actually saying that only on the 4165 the poker hand will you get a four‑of‑a‑kind, not just on any of the 4165 poker hands.
C. The probability is actually saying that in the long run, with a large number of five‑card poker hands, the fraction in which you will be dealt a four‑of‑a‑kind is 1 / 4165.
D. The chance you will be dealt four‑of‑a‑kind is 1 / 4165 only on the first hand. This chance will then increase with each new hand you are dealt until you eventually win
Answer:
B) [1, 4, 7]
Step-by-step explanation:
Substitute 0 in
f(0) = 3(0) + 1
Multiple
f(0) = 0 + 1
f(0) = 1
Substitute 1 in
f(1) = 3(1) + 1
f(1) = 3 + 1
f(1) = 4
Substitute 2 in
f(2) = 3(2) + 1
2 = 6 + 1
f(2) = 7
Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°
<u>Step-by-step explanation:</u>
Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL
KM ≅ LM
3x + 23 = 7x - 37
23 = 4x - 37
60 = 4x
15 = x
KM = LM = 3x + 23
= 3(15) + 23
= 45 + 23
= 68
KL = 9x - 40
= 9(15) - 40
= 135 - 40
= 95
Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.
- Since N is the midpoint of KL and KL = 95, then NL = 47.5
- Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse
Use trig to solve for ∠L (which equals ∠K):
cos ∠L = 
cos ∠L = 
∠L = cos⁻¹ 
∠L = 45.7
Triangle sum Theorem:
∠K + ∠L + ∠M = 180°
45.7 + 45.7 + ∠M = 180
91.4 + ∠M = 180
∠M = 88.6
Answer:
Let total number of dog and cat population in animal shelter be x.
As per the statement:
An animal shelter has 9 puppies.
⇒ Total number of puppies = 9
It is also given that if the puppies are 36% of the total dog and cat population.
⇒ 
or

By cross multiply we get;

Divide both sides by 36 we get;

Therefore, total number of dogs and cat population in animal shelter are 25
Answer:
The horizontal segment of E and vertical segments of M.
Step-by-step explanation: