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2 years ago

1. Why is soil erosion relatively less in dense forests as compared to barren, open fields?

Chemistry

2 answers:

vredina [299]2 years ago

8 0

Because the deep roots of big trees hold the soil and don't let it slip away simply by rain or wind.

Korvikt [17]2 years ago

4 0

Answer:

the roots of the trees keep the soil in place opposed to a barren landscape that has little to no plants to keep the soil in place

hope this helps (╹ڡ╹ )

You might be interested in

What is an example of how enginers contrbiuted to society

SpyIntel [72]

Answer:

Engineers changed the world, such as building houses, bridges, and cars.

Please rate it the brainlist if this helped you and let me know if you have any questions, thanks

8 0

3 years ago

under certain water conditions, the free chlorine (hypochlorous acid, hocl) in a swimming pool decomposes according to the la

ivolga24 [154]

Answer:

1.7 ppm

Explanation:

Original amount N' = 2.6 ppm

time to testing t = 24 hr

final amount N = 2.1 ppm

Using exponential inhibited decay, we have

N = N'e^(-kt)

Where

N is the new reading

N' is the original reading

t is the decay time

k is the decay constant

Substituting, we have

2.1 = 2.6 x e^(-k x 24)

2.1 = 2.6 x e^(-24k)

0.808 = e^(-24k)

We take the natural log of both sides of the equation

Ln 0.808 = Ln (e^(-24k))

-0.213 = - 24k

K = 0.213/24 = 0.00886

After 48 hrs, the reading of free chlorine will be

N = 2.6 x e^(-0.00886 x 48)

N = 2.6 x e^(-0.425)

N = 2.6 x 0.654

N = 1.7 ppm

5 0

3 years ago

In a synthesis reaction you start with 1.7L of Hydrogen how many liters of water will be produced?

jolli1 [7]

15.3 litres of water will be produced if we take 1.7 litres of Hydrogen

Explanation:

Let's take a look over synthesis reaction;

$H_{2}+ O_{2}$ $H_{2}O$

Balancing the chemical reaction;

$2H_{2} +O_{2}$ $2H_{2}O$

Thus, 2 moles of hydrogen molecules are required to form 2 moles of water molecules.

Equating the molarity;

$\frac{1.7*1}{2*2}$ = $\frac{x*1}{2*18}$

(Since, the molecular mass of hyd and water is 2 and 18 respectively)

x= $\frac{1.7*2*18}{2*2}$

x= 15.3 litres.

Thus,15.3 L of water will be produced if we take 1.7 litres of Hydrogen in a synthesis reaction.

6 0

3 years ago

What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi

Zepler [3.9K]

Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an exothermic reaction. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, Quantity of heat, q = mass * specific heat capacity * temperature rise.

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0

3 years ago

Calculate the volume of a balloon that can hold 113.4 g of nitrogen dioxide, NO2 gas at STP-

Karolina [17]

Answer:

55.18 L

Explanation:

First we convert 113.4 g of NO₂ into moles, using its molar mass:

113.4 g ÷ 46 g/mol = 2.465 mol

Then we use the PV=nRT formula, where:

P = 1atm & T = 273K (This means STP)

n = 2.465 mol

R = 0.082 atm·L·mol⁻¹·K⁻¹

V = ?

Input the data:

1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K

And solve for V:

V = 55.18 L

6 0

2 years ago