1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Novay_Z [31]
3 years ago
15

Number of moles of Sn (l) produced when 4.0 moles of H2 (g) is completely consumed

Chemistry
1 answer:
Dafna11 [192]3 years ago
4 0
The answer is 2.0 moles.
From their coefficients in the balanced chemical equation below for the reaction of tin dioxide with hydrogen gas to produce tin and water:
     SnO2(s) + 2H2(g) ==>Sn(l) + 2H2O(g)
two moles of hydrogen gas is to produce one mole of tin. We use this mole ratio to compute for the number of moles of tin as:
     moles of Sn = 4.0mol H2 (1mol Sn/2mol H2) = 2.0 mol
You might be interested in
1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium
lilavasa [31]

Answer:

This question is incomplete, here's the complete question:

1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

Buffer A

Mass of sodium acetate used: 0.3730 g

Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

Concentration of standardized NaOH 0.100M

moles of Naoh needed to change the ph by 1 unit for the buffer 0.00095mol

the buffer capacity 0.0475 M

Buffer B

Mass of sodium acetate used 1.12 g

Actual pH of the buffer 5.34

Volume of the buffer used in buffer capacity titration 20.0 mL

Concentration if standardized NaOH 0.100 M

moles of Naoh needed to change the ph by 1 unit 0.0019 mol

the buffer capacity 0.095 M

2.) A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in #1 by a factor of 10 for each buffer. Are there any differences between your experimental results and the theoretical calculation?

3.) which buffer had a higher buffer capacity? Why?

Explanation:

Formula,

moles = grams/molar mass

molarity = moles/L of solution

1. Buffer A

molarity of NaC2H3O2 = 0.3731 g/82.03 g/mol x 0.02 L = 0.23 M

molarity of HC2H3O2 = 0. 1 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.23/0.1)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

Buffer B

molarity of NaC2H3O2 = 1.12 g/82.03 g/mol x 0.02 L = 0.68 M

molarity of HC2H3O2 = 0.3 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.68/0.3)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

2. let x moles of NaOH is added,

Buffer A,

pH = 5.10

[H3O+] = 7.91 x 10^-6 M

new pH = 4.10

new [H3O+] = 7.91 x 10^-5 M

moles of NaOH to be added = (7.91 x 10^-5 - 7.91 x 10^-6) x 0.02 L

= 1.42 x 10^-6 mol

3. Buffer B with greater concentration of NaC2H3O2 and HC2H3O2 has higher buffer capacity as it resists pH change to a wider range due to addition of acid or base to the system as compared to low concentration of Buffer A

5 0
3 years ago
Identify the products and the reactants in the following chemical equations
liq [111]

Answer:

1-Mg+O2=reactants                  MgO-product

2-CaNr2+AlCl3=reactants        CaCI2+AIBr3=product

3-C2H4+O2=reactants              H2O+CO2=product

Explanation:

Reactants are on the left side and products on the right.

6 0
2 years ago
Which of the following is an example of a chemical change?
wolverine [178]

Answer:

C

Explanation:

6 0
2 years ago
Read 2 more answers
A saturated hydrocarbon is an organic compound which contains hydrogen and carbon joined _____.
Leya [2.2K]
B) with single bonds..... Hope it helps, Have a nice day :)
8 0
3 years ago
Read 2 more answers
You are given 230 grams of a substance with a half-life of 0.75 years. How much will remain after 3 years?
Degger [83]
After 3 years, the substance will go through 4 half lives. You can do 230*(1/2)^4, which is 14.375.
6 0
3 years ago
Other questions:
  • If bacteria tried to “friend” you one Facebook, why would you accept? Why would
    9·1 answer
  • 2. Oxygen can combine with carbon to form two compounds, carbon monoxide, and carbon dioxide. The ratio of the masses of oxygen
    5·1 answer
  • Without doing any calculations, which transition in the hydrogen atom has the shortest wavelength?
    6·1 answer
  • A solution is prepared by dissolving 1.86g of kcl and 8.29g of k2co3 in enough water to make uo the final volume of 500 cm3. Wha
    12·1 answer
  • What is the electron configuration for oxygen with a 2- charge (o2-)?
    15·1 answer
  • Which essential amino acid helps to alleviate insomnia and can be found in turkey?
    7·2 answers
  • Someone plz answer this
    8·2 answers
  • What happens to temperature as objects are heated up and cooled down?
    6·1 answer
  • A 5.00 cm^3 sample of gold has a mass of 96.5 g. Calculate the density of gold.
    6·1 answer
  • Prove the following:V=U + AT<br>​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!