What is the percent composition of silicon dioxide, SiO2 ? (Atomic masses : O = 16 . 0 Si =28 .1

Measure out 2.87 moles of sodium chloride (Nacl) into a clean dry cup.

Anettt [7]

Answer: weigh is m = n × M = 2.87 mol × 58.44 g/mol

Explanation: mass = amount of substance × molar mass

M((NaCl) = 22.99 +35.45

6 0

2 years ago

3. The diet of white-tailed deer consists primarily of shrubs. Sika are

olga_2 [115]

Sika have more food choices because they eat both grasses and shrubs, compared to the white-tailed dear who only eats shrubs.

3 0

2 years ago

The balloon is removed from the freezer and returned to its initial conditions. It is then heated to a tempatuew of 2T at a pres

slavikrds [6]

Answer:

answer: It does not change

Explanation:

7 0

3 years ago

what mass of hgbr2 can be produced from the reaction of 5.00 ml mercury (density = 13.6 g/mL) and 5.00 ml bromine (density = 3.1

Katarina [22]

Jsnsbshhsbshdjjshsbshd

5 0

3 years ago

A 1.00 kg sample of Sb2S3 (s) and a 10.0 g sample of H2 (g) are allowed to react in a 25.0 L container at 713 K. At equilibrium,

Scorpion4ik [409]

Answer: The value of $K_c$ is coming out to be 0.412

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For $Sb_2S_3$

Given mass of $Sb_2S_3$ = 1.00 kg = 1000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of $Sb_2S_3$ = 339.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of }Sb_2S_3=\frac{1000g}{339.7g/mol}=2.944mol$

For hydrogen gas:

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol$

For hydrogen sulfide:

Given mass of hydrogen sulfide = 72.6 g

Molar mass of hydrogen sulfide = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen sulfide}=\frac{72.6g}{34g/mol}=2.135mol$

The chemical equation for the reaction of antimony sulfide and hydrogen gas follows:

$Sb_2S_3(s)+3H_2(g)\rightarrow 2Sb(s)+3H_2S(g)$

Initial: 2.944 5

At eqllm: 2.944-x 5-3x 2x 3x

We are given:

Equilibrium moles of hydrogen sulfide = 2.135 moles

Calculating for 'x', we get:

$\Rightarrow 3x=2.135\\\\\Rightarrow x=\frac{2.135}{3}=0.712$

Equilibrium moles of hydrogen gas = (5 - 3x) = (5 - 3(0.712)) = 2.868 moles

Volume of the container = 25.0 L

Molarity of a solution is calculated by using the formula:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}$

The expression of $K_c$ for above equation, we get:

$K_c=\frac{[H_2S]^3}{[H_2]^3}$

The concentration of solids and liquids are not taken in the expression of equilibrium constant.

$K_c=\frac{(\frac{2.135}{25})^3}{(\frac{2.868}{25})^3}\\\\K_c=0.412$

Hence, the value of $K_c$ is coming out to be 0.412

3 0

3 years ago