What is the percent composition of silicon dioxide, SiO2 ? (Atomic masses : O = 16 . 0 Si =28 .1

Chemistry

1 answer:

weeeeeb [17]3 years ago

4 0

Answer:

60.1 i think

Explanation:

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Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s

Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

$N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}$

where N is amount of radioactive nuclide after t time, $N_{0}$ is initial amount of radioactive nuclide and $t_{\frac{1}{2}}$ is half life of radioactive nuclide

Here $N_{0}=4.60 mg$ , $t=4.1\times 10^{9}yr$ and $t_{\frac{1}{2}}=4.5\times 10^{9}yr$

So, $N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}$

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0

3 years ago

What mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

nikitadnepr [17]

The mass of water produced by the reaction of the 23 g of $SiO_2$ is 13.8 g.

The given chemical reaction;

$4Hf (g) \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)$

In the given compound above, we can deduce the following;

molecular mass of $SiO_2$ = 28 + (2 x 16) = 60 g
molecular mass of $2H_2O$ = 2(18) = 36 g

60 g of $SiO_2$ --------- 36 g of water

23 g of $SiO_2$ ------------- ? of water

$mass \ of \ water = \frac{23 \times 36}{60} = 13.8 \ g \ of \ water$

Thus, the mass of water produced by the reaction of the 23 g of $SiO_2$ is 13.8 g.

<em>"Your question is not complete, it seems to be missing the following information";</em>

In the reaction of the given compound, $4Hf (g) \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)$ , what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

Learn more here:brainly.com/question/13644576

5 0

2 years ago

3-ethyl-2-methyl-2-pentene

gayaneshka [121]

See photo for drawing :)