Answer:
2.15 mg of uranium-238 decays
Explanation:
For decay of radioactive nuclide-

where N is amount of radioactive nuclide after t time,
is initial amount of radioactive nuclide and
is half life of radioactive nuclide
Here
,
and 
So,
so, N = 2.446 mg
mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg
The mass of water produced by the reaction of the 23 g of
is 13.8 g.
The given chemical reaction;

In the given compound above, we can deduce the following;
- molecular mass of
= 28 + (2 x 16) = 60 g - molecular mass of
= 2(18) = 36 g
60 g of
--------- 36 g of water
23 g of
------------- ? of water

Thus, the mass of water produced by the reaction of the 23 g of
is 13.8 g.
- <em>"Your question is not complete, it seems to be missing the following information";</em>
In the reaction of the given compound,
, what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?
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