Answer:
11.3 g of H₂O will be produced.
Explanation:
The combustion is:
2C₈H₁₈ + 25O₂→ 16CO₂ + 18H₂O
First of all, we determine the moles of the reactants in order to find out the limiting reactant.
8 g / 114g/mol = 0.0701 moles of octane
37g / 32 g/mol = 1.15 moles of oxygen
The limiting reagent is the octane. Let's see it by this rule of three:
25 moles of oxygen react to 2 moles of octane so
1.15 moles of oxygen will react to ( 1.15 . 2)/ 25 = 0.092 moles of octane.
We do not have enough octane, we need 0.092 moles and we have 0.0701 moles. Now we work with the stoichiometry of the reaction so we make this rule of three:
2 moles of octane produce 18 moles of water
Then 0.0701 moles of octane may produce (0.0701 . 18)/2= 0.631 moles of water.
We convert the moles to mass → 0.631 mol . 18 g/1mol = 11.3 g of H₂O will be produced.
<h3>
Answer: 386.67 g/mol </h3>
Explanation:
Molar Mass = Mass ÷ Mole
= 0.406 g ÷ 0.00105 mol
= 386.67 g/mol
∴ molar mass of cholesterol = 386.67 g/mol
Answer:
water has a high specific heat
Explanation:
this should work as an answer
Answer:
The answer to your question is pH = 6.3
Explanation:
Data
pH = ?
[H⁺] = 4.73 x 10⁻⁷ M
pH is the measure of the concentration of [H⁺]. pH measures the acidity of the solution. If the value of pH is between 0 and 6.9, the solution is an acid. If the pH is 7.0 the solution is neutral and if the pH is between 7.1 and 14, the solution is an alkali.
Formula
pH = -log[H⁺]
Substitution
pH = -log[4.73 x 10⁻⁷]
-Simplification
pH = - (-6.3)
-Result
pH = 6.3
