The mole ratio for the reaction between $HNO_3$ and $Na_2CO_3$ is 1:2. This means 1 moles of $Na_2CO_3$ will neutralize 2 moles $HNO_3$ . Now we find the moles of each reactant based on the mass and molar mass.

$2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3$

$2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3$

$\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}$

The $Na_2CO_3$ was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0

3 years ago

When two metals touch in the mouth, a small shock is created. this is known as<br> a?

Over [174]

<span>When two metals touch in the mouth, a small shock is created. this is known as a </span>galvanic action

7 0

3 years ago

What functions of cells can be affected by a mutation?

Colt1911 [192]

It changes the rate of growth that cells usually undergo.

6 0

3 years ago

MULTIPLE CHOICE

adelina 88 [10]

Answer:

C 2

Explanation:

2Nal + Cl2 → 2NaCl + I2

This is balanced equation

6 0

2 years ago