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notsponge [240]
3 years ago
14

Triangle A B C is reflected over side A C and then is dilated to form smaller triangle D E C. Angles B C A and D C E are right a

ngles. Right triangle ABC is reflected over AC, then dilated by a scale factor of Two-thirds to form triangle DEC. Which statements about the two triangles must be true? Select three options. △ABC ~ △DEC ∠B ≅ ∠E 3BC = 2EC 3DE = 2AB 3m∠A = 2m∠D 2m∠A = 3m∠D
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

A. △ABC ~ △DEC

B. ∠B ≅ ∠E

D. 3DE = 2AB

Step-by-step explanation:

Transformation involves the reshaping or resizing of a given figure. The types are: reflection, dilation, rotation and translation.

In the given question, the two operations performed on triangle ABC are reflection and dilation to form triangle DEC. The length of each side of triangle DEC is two-third of that of ABC. Therefore, the correct statements about the two triangles are:

i. △ABC ~ △DEC

ii. ∠B ≅ ∠E

iii. 3DE = 2AB

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3 years ago
Sam and Bruno were computing how many kilometers they rode in the 3 bike trips they took last month. In order, they rode 45.7, 4
Eddi Din [679]

Answer:

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Sam and Bruno were computing how many kilometers.

Also one kilometer equals 0.621 miles.

From this we can see than 1 kilometer is smaller unit and a mile is a larger unit.

In order to convert number of miles into kilometers, we need to divide each number of mile by 0.621 miles.

We always divide a larger value by a smaller value to get the smaller unit.

Therefore,

Bruno is correct. When going from a larger unit to a smaller unit you need to divide.

Step-by-step explanation:

Hopefully this helped, if not HMU and I will get u a better answer.

<em>-Have a great day! :)</em>

4 0
3 years ago
A 12-ft ladder is leaning on a building. If the base of the ladder is placed 5 feet from the building, approximately how high do
Citrus2011 [14]
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3 0
3 years ago
Read 2 more answers
(1+tanx)/(sinx+cosx)=secx
jek_recluse [69]

\frac{1+\tan x}{\sin x+\cos x}=\sec x is proved

<h3><u>Solution:</u></h3>

Given that,

\frac{1+\tan x}{\sin x+\cos x}=\sec x  ------- (1)

First we will simplify the LHS and then compare it with RHS

\text { L. H.S }=\frac{1+\tan x}{\sin x+\cos x}  ------ (2)

\text {We know that } \tan x=\frac{\sin x}{\cos x}

Substitute this in eqn (2)

=\frac{1+\frac{\sin x}{\cos x}}{\sin x+\cos x}

On simplification we get,

=\frac{\frac{\sin x+\cos x}{\cos x}}{\sin x+\cos x}

=\frac{\sin x+\cos x}{\cos x} \times \frac{1}{\sin x+\cos x}

Cancelling the common terms (sinx + cosx)

=\frac{1}{c o s x}

We know secant is inverse of cosine

=\sec x=R . H . S

Thus L.H.S = R.H.S

\frac{1+\tan x}{\sin x+\cos x}=\sec x

Hence proved

5 0
3 years ago
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Answer:

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