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topjm [15]
2 years ago
12

2. John and Jen went to the farmers market to buy fruit. John bought 3 boxes of oranges and 9 boxes of cherries for $78. Jen bou

ght 8 boxes of oranges and 4 boxes cherries for $58. The system of equations ( shown in the pic i uploaded) can be used to represent this situation. A. Find how much does a box of oranges and a box of cherries cost ?

Mathematics
1 answer:
jenyasd209 [6]2 years ago
7 0

Answer:

Let the cost of orange be X and cost of cherry be y

3x + 9y = 78

8x + 4y = 58

Solving equation using elimination method

multiplying eq 1 with 8 and eq 2 with 3

8(3x + 9y ) = 78(8)

3( 8x + 4y) = 3(58)

24x + 72 y = 624

24x + 12y = 174

subtracting,

60 y = 450

y = 7.5

3x + 9(7.5) = 78

3x + 67.5 = 78

3x = 78 - 67.5

3x = 10.5

x = 3.5

<h2>Box of orange = $3.5 </h2><h2>Box of cherry = $7.5</h2>
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ziro4ka [17]

Answer:

12

Step-by-step explanation:

The total area is 48 and the value of x is 36 (figure 1)

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3 0
3 years ago
What is the solution to 6 (5x – 2) = -72?<br> A: x = -2<br> B: x = -14/5<br> C: x = 2<br> D: x= -7/3
aliina [53]

Answer:

Step-by-step explanation:

6(5x - 2) = -72

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30x = -60

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answer is A

6 0
4 years ago
Read 2 more answers
It has been hypothesized that the standard deviation of the germination time of radish seeds is 8 days. The standard deviation o
Yanka [14]

Answer:

\chi^2 =\frac{60-1}{64} 36 =33.19

The degrees of freedom are:

df= n-1= 60-1= 59

And the p value would be given by:

p_v =2*P(\chi^2 >33.19)=0.0053

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

Step-by-step explanation:

Data given

n=60 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =6^2 =36 represent the sample variance obtained

\sigma^2_0 =8^=64 represent the value that we want to test

Hypothesis to test

We want to verify if the true deviation is equal to 8 days o not, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 64

Alternative hypothesis: \sigma^2 \neq 64

The statistic is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

Replacing we got:

\chi^2 =\frac{60-1}{64} 36 =33.19

The degrees of freedom are:

df= n-1= 60-1= 59

And the p value would be given by:

p_v =2*P(\chi^2 >33.19)=0.0053

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true deviation is different from 8 days.

6 0
4 years ago
Four times a number plus three is the same as six plus the number
statuscvo [17]

Answer:

4x+3=6+x

x=1

Step-by-step explanation:

4x+3=6+x

3x+3=6

3x=3

x=1

6 0
3 years ago
Read 2 more answers
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