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Answer:
Explanation:
The pressures given are relative
p1 = 2000 psi
P1 = 2014 psi = 13.9 MPa
p2 = 4 psi
P2 = 18.6 psi = 128 kPa
Values are taken from the steam pressure-enthalpy diagram
h2 = 2500 kJ/kg
If the output of the turbine has a quality of 85%:
t2 = 106 C
I consider the expansion in the turbine to adiabatic and reversible, therefore, isentropic
s1 = s2 = 6.4 kJ/(kg K)
h1 = 3500 kJ/kg
t2 = 550 C
The work in the turbine is of
w = h1 - h2 = 3500 - 2500 = 1000 kJ/kg
The thermal efficiency of the cycle depends on the input heat.
η = w/q1
q1 is not a given, so it cannot be calculated.
Answer:
D
Explanation:
in series circuit the resistance is divided Total resistance is equal to the sum of resistances
Answer:
percentage change in volume = 0.00285 %
Explanation:
given data
bulk modulus = 3.5 ×
N/m²
bulk stress =
N/m²
solution
we will apply here bulk modulus formula that is
bulk modulus =
...............1
put here value and we get
3.5 ×
=
solve it we get
bulk strain = 2.8571 ×
and
bulk strain =
so that percentage change in volume is = 2.8571 ×
× 100
percentage change in volume = 0.00285 %