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ycow [4]
3 years ago
10

Question 2

Engineering
1 answer:
Svetllana [295]3 years ago
5 0

Analyzing the information from the case above, the ideal would be Sarah to schedule a meeting with your boss to expose the facts and seek a solution, as this is an ethical dilemma that she became aware of and as a new manager she will have to deal with it.

She became aware of an illegal practice that has become part of the company's culture and that her boss is aware of this illegality.

Sarah needs to be aware that her talk about the possibility of changing company policy and complying with ethics could jeopardize her job.

But on the other hand, if Sarah's boss does not accept to change the company's ethical parameters, she will also be running the risk of being part of this illegal act and damaging her reputation.

Therefore, the best option for Sarah is to be honest and talk to her boss about the situation.

In this way, it can help workers receive their rights, if their argument is accepted, and transform the company into an ethical place with a culture focused on the development and compliance with ethics and legislation.

Learn more here:

brainly.com/question/22204062

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In c the square root of a number N can be approximated by repeated calculation using the formula NG = 0.5(LG + N/LG) where NG st
DanielleElmas [232]

Answer:

Following are the program to the given question:

#include <stdio.h>//header file

double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters

{

double NG, LG = initialGuess,diff;//defining double variable

while(1)//use loop to calculate square root value

{

NG = 0.5 * (LG + N / LG);//using given formula

diff = NG - LG;//calculating difference

if(diff < 0)//use if to check difference is less than 0

diff = -diff;//decreaing difference

if(diff < 0.005)//use if that check difference is less than 0.005

break;//using break keyword  

else//defining else block

{

LG = NG;//holding value

}

}

return NG;//return value

}

int main()//defining main method

{

double ans, n,initialguess = 1.0;//defining double variable

n = 4;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 120.5;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 36.01;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 0.25;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

printf("\nEnter a number: ");//print message

scanf("%lf", &n);//input value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

}

Output:

Please find the attachment file.

Explanation:

  • In this code, a method "square_root" is declared that takes two variable "N, initialGuess" in its parameters, inside the method a three double variable is declared.
  • It uses the given formula and uses the diff variable to hold its value and uses two if to check its value is less than 0 and 0.005 and return its calculated value.
  • In the main method, three double variables are declared that use the "n" to hold value and "ans" to call the method that holds its value and print its value.

8 0
3 years ago
Help thank you &lt;3 :DDD
Vika [28.1K]

Answer:

Explanation:

its B

4 0
3 years ago
An elastic cable is to be designed for bungee jumping from a tower 130 ft high. The specifications call for the cable to be 85 f
azamat

Answer:

<em>a) The spring constant is 50 lb/ft</em>

<em>b) The man is 26.3 ft close to the ground.</em>

<em></em>

Explanation:

Height of tower is 130 ft

Specification calls for a cable of length 85 ft

the maximum this length stretches is 100 ft when subjected to a load of 750 lb

The extension of the cable is calculated from the formula from Hooke's law

F = kx

where F is the load or force on the cable

k is the spring constant of the cable

x is the extension on the cable

a) The extension on the cable is

x = 100 ft - 85 ft = 15 ft

substituting into the formula above, we'll have

750 = k*15

k = 750/15 = <em>50 lb/ft</em>

b) for a 185 lb man, jumping down will give an extension gotten as

F = kx

185 = 50*x

x = 185/50 = 3.7 ft

The total length of the cable will be extended to 100 ft + 3.7 ft = 103.7 ft

closeness to the ground = 130 ft - 103.7 ft =<em> 26.3 ft</em>

3 0
3 years ago
A piston-cylinder assembly contains 2 lb of air at a temperature of 540 degrees R and a pressure of 1 atm. The air is compressed
attashe74 [19]

Answer:

W=-123.8Btu

Explanation:

Hello,

In this problem, the piston-cylinder assembly make us state the energy balance as:

Q-W=\Delta U

Thus, we must now compute \Delta U in terms of Cv as follows:

\Delta U=mCv(T_2-T_1)\\\Delta U=2lb*0.173\frac{Btu}{lb*R}*(840R-540R)\\ \Delta U=103.8Btu

Now, since heat is given off, its sign is negative, thus, the work is computed as:

W=Q-\Delta U\\W=-20Btu-103.8Btu=-123.8Btu

This work means that work was done over the system in order to allow the compression.

The suppositions were:

- The change in the internal energy is a function of the temperature.

- Air is an ideal gas.

Best regards.

8 0
4 years ago
A hollow, spherical shell with mass 2.00kg rolls without slipping down a slope angled at 38.0?.
mezya [45]

Answer:

\mu = 0.31

Explanation:

Given data:

mass = 2.00 kg

slope angle = 38.0

From figure

balancing force

mgsin\theta - f = ma   .....1

Balancing torque

F_R = \frac{2}{3} mR^2 \alpha ......2

for pure rolling

\alpha  = \frac{a}{R}

F = \frac{2}{3} ma

from 1 and 2nd equation

mgsin\theta - \frac{2}{3}ma =  ma

mgsin\theta = \frac{5}{3} ma

a = \frac{3}{5} g sin\theta

 = \frac{3\theta 9.8 sin 38}{5} = 3.62 m/s^2

F =\mu N

   = \frac{2}{3} ma

   = \frac{2}{3} 2\times 3.62 = 4.83 N

N =normal force =  mgsin\theta = 2 \times 9.8 sin 38 = 15.44 N

\mu \times 15.44 = 4.83

solving for  coefficent of friction we get

\mu = 0.31

4 0
3 years ago
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