Technician A says that the first step in diagnosing engine condition is to perform a thorough visual inspection. Technician B sa
1 answer:
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Answer:
a). Work transfer = 527.2 kJ
b). Heat Transfer = 197.7 kJ
Explanation:
Given:
= 5 Mpa
= 1623°C
= 1896 K
= 0.05
Also given
Therefore, = 1
R = 0.27 kJ / kg-K
= 0.8 kJ / kg-K
Also given :
Therefore, =
= 0.1182 MPa
a). Work transfer, δW =
= 527200 J
= 527.200 kJ
b). From 1st law of thermodynamics,
Heat transfer, δQ = ΔU+δW
=
=
=
= 197.7 kJ
Answer:
a) Cr = Co - Fx / D
b) ΔC / Δx = ( CR - Cr ) / ( xR - xRo )
Explanation:
A) Derive an expression for the profile c(r) inside the tissue
F = DΔC / X = D ( Co - Cr ) / X ------ 1
where : F = flux , D = drug diffusion coefficient
X = radial distance between Ro and R
Hence : Cr = Co - Fx / D
B) Express the diffusive flux at outer surface of the balloon
Diffusive flux at outer surface = ΔC / Δx = CR - Cr / xR - xRo
