Answer:
Hey kimalonzo59!
· Calculate specific heat as c = Q / (mΔT). In our example, it will be equal to c = -63,000 J / (5 kg * -3 K) = 4,200 J/ (kg·K). This is the typical heat capacity of water.
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im not too sure but the answer above helps a lot
dont know
Explanation:
Na+ is positively charged as it loses an electron
Cl- is negatively charged as it gains an electron
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