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3 years ago

9

Adding a catalyst decreases the rate of a reaction. If the rate increases, then either k increases or the order of the reaction

changes. What experiments might you perform to discover which is occurring?

1 answer:

qaws [65]3 years ago

4 0

Answer:

Soaponification/esterification or fermentation

Explanation:

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A student dissolves of urea in of a solvent with a density of . The student notices that the volume of the solvent does not chan

Dimas [21]

The question incomplete , the complete question is:

A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.

Answer:

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

Explanation:

Moles of urea = $\frac{18.0 g}{60 g/mol}=0.3 mol$

Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

$Molarity(M)=\frac{\text{Moles of compound}}{\text{Volume of solution in L}}$

Molarity of the urea solution ;

$M=\frac{0.3 mol}{0.200 L}=1.50 M$

Mass of solvent = m

Volume of solvent = V = 200.0 mL

Density of the urea = d = 0.95 g/mL

$m=d\times V=0.95 g/mL\times 200.0 mL=190 g$

$m = 190 g = 190 \times 0.001 kg = 0.19 kg$

(1 g = 0.001 kg)

Molality of the urea solution ;

$Molality(m)=\frac{\text{Moles of compound}}{\text{Mass of solvent in kg}}$

$m=\frac{0.3 mol}{0.19 kg}=1.58 m$

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

7 0

3 years ago

Do biotic factors contain cells

Keith_Richards [23]

Yes, anything that lives. Cells have a nucleus, they are alive and can reproduce. (Not man made/abiotic)

7 0

3 years ago

What is the electron configuration of Mn3+

Mumz [18]

Answer:

The electron configuration for a

Mn3+ ion is [Ar]3d4

Explanation:

4 0

3 years ago

S8 + 12 O2 → 8 SO3<br>How many moles of SO3 can be produced from 6 moles of O2?

MA_775_DIABLO [31]

Answer:

4 moles of SO3 will be produced from 6 moles of oxygen.

Explanation:

From the reaction given

S8 + 12 O2 ----> 8 SO3

12 moles of oxygen reacts to form 8 moles of SO3

if 6 moles of oxygen were to be used instead, it has been reduced to half of the original mole of oxygen used. Then the moles of SO3 will also be reduced to half.

6 moles of O2 will yield 4 moles of SO3

12 moles = 8 moles

6 moles = ?

? = 6 * 8 / 12

? = 48/ 12

? = 4 moles of SO3.

8 0

3 years ago

Fill in the blanks and correct anything that you think is wrong. Please?

kap26 [50]

you are right on all the ones you did

8 0

3 years ago