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gogolik [260]
2 years ago
9

Adding a catalyst decreases the rate of a reaction. If the rate increases, then either k increases or the order of the reaction

changes. What experiments might you perform to discover which is occurring?
Chemistry
1 answer:
qaws [65]2 years ago
4 0

Answer:

Soaponification/esterification or fermentation

Explanation:

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One isotope of carbon has 6 protons and 6 neutrons. The number of protons and neutrons of a second isotope of carbon would be __
dexar [7]
D. 6 protons and 7 neutrons

As proton remains constant
6 0
3 years ago
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How many moles of Cl2 will produce 0.35 miles of NaCl when reacted with excess Na?
weeeeeb [17]
This question is based in mole ratios. for every mole of cl2, 2 moles of NaCl will be produced. so half of the moles of NaCl gives the moles of Cl2 required. therefore divide 0.35 by 2
6 0
3 years ago
Protons and neutrons are composed of what?<br> A electrons<br> B.quarks<br> C.ions<br> D.molecules
leonid [27]
B. Quarks is the answer.
6 0
3 years ago
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A stain is made up of molecules that do not have charged regions. What soap/solvent combination should I use?Are there multiple?
Dmitry_Shevchenko [17]

Answer:

The answer is below

Explanation:

Yes, there are multiple combinations.

Firstly, a solvent or soap combination could be used as a polar solvent with soap. In this way, the nonpolar region of the soap molecules would mix directly with the stain while the solvent would surround the soap-stain micelle.

Secondly, another method or way is to have a combination of a nonpolar solvent with no soap. In this method, however, it is the solvent that would mix directly with the stain.

4 0
2 years ago
The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
Sladkaya [172]

Answer:

\boxed{3.6}

Explanation:

                  2NO₂ ⇌ N₂O₄

E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

7 0
3 years ago
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