Answer:
See the attached file for the answers.
Step-by-step explanation:
See the attached file for the explanation
Answer:
X=120
Step-by-step explanation:
It is an equalateral so all the angles in the middle are the same all being 60
The angle of a straight line is 180
So just minus 60 from 180 to get 120
180-60=120
Begin by using the cosine rule to find the unknown side.
Where a- unknown side, b is 12, c is 16 and angle in between is 108°
The cosine rule...
a² = b² + c² - 2bc cosA
= 12² + 16² - (2×12×16 cos108°)
= 518.655076
Taking the positive
square root...
a = 22.774
a = 22.8 cm nearest tenth
Answer:
C
Step-by-step explanation:
y-3=5(x-2) (rearrange this to be in slope- intercept from) (add 3 to both sides)
y = 5(x-2) + 3 (distribute parentheses)
y = x(5) - 2(5) + 3
y = 5x -10 + 3
y = 5x - 7
recall that for a line with gradient m, the gradient of the perpendicular line will be - (1/m)
hence in our case, our gradient of the original line is 5, hence the gradient of the perpendicular line is -1/5
From the choices, the only one that is consistent with this is C
i.e choice C:
5y + x = 25
5y = -x + 25
y = -(1/5) x + 5 ===> gradient of -1/5
Answer:
ABQ = 139
BCR is the same as QBC since they are alternate interior angles
BCR = 41
Step-by-step explanation:
CBQ and SCB are same side interior angles so they add to 180
2a-9 + 5a +14 = 180
Combine like terms
7a +5 = 180
Subtract 5 from each side
7a = 175
Divide by 7
7a/7 = 175/7
a = 25
ABQ is the same as SCB since they are corresponding angles so
ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139
BCR is the same as QBC since they are alternate interior angles
BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41
