10 for his brother and 5 for his friends
Each time it increases by 0.4
0 - 0.4 - 0.8 - 1.2 - 1.6 - 2.0 - 2.4 - 2.8 - 3.2 etc.
The answer is 262 and I hope you have a nice week yours ac80922
Answer:
The possible values for 1/y of the expression 0.125 < y < 0.25 are in the range
4 < 1/y < 8
Step-by-step explanation:
The given information are;
The range of values of y are 0.125 < y < 0.25, therefore, we have;
The boundaries of the function, y are 0.125 and 0.25
The inverse of the boundaries of the function, y are 1/0.125 = 8 and 1/0.24 = 4
Therefore;
The limits of the inverse of the function y are ;
The inequality that represents 1/y is therefore;
1/0.25 < 1/y < 1/0.125 or 4 < 1/y < 8
The possible values of 1/y for the expression 0.125 < y < 0.25 are therefore;
4 < 1/y < 8.
Best to factor 5 out of the first 2 terms:
5x^2-7x+2=0 => <span>5(x^2 - [7/5]x) +2=0
Take half of [-7/5]: That'd be -7/10.
Square 7/10, add it to </span>5(x^2 - [7/5]x) +2=0 and then subtract it:
5(x^2 - [7/5]x)+ 49/100 - 49/100 ) +2=0
Then we have 5(x- [7/10] )^2 - 49/100 ) + 200/100 = 0
5(x-7/5)^2 - 245/100 + 200/100 = 0
5(x-7/5)^2 - 45/100 = 0
Dividing all terms by 5, x-7/5 = plus or minus sqrt( 9/100 )
x-7/5 = plus or minus 3/10
Then one root is x = 7/5 + 3/10, or x= 17/10 (answer #1)
The other is x = 7/5 - 3/10, or x = 14/10 - 3/10, or x = 7/10 (answer #2)
