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3 years ago

Question 2 of 5

Mathematics

1 answer:

Fiesta28 [93]3 years ago

8 0

I agree it’s D. Hope it helps

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Not sure how to complete #14

pashok25 [27]

14. Add the line times the outside number
X(X+4)= (2√3)^2
X^2+4X= 4√9
X^2+4X= 4times 3
X^2+4X=12
X^2+4X-12=0
(X+6)(X-2)=0
X=-6 X=2
Answe can't be negative so it's X=2

3 0

2 years ago

A pizza shop sells pizzas that are 10 inches (in diameter) or larger. A 10-inch cheese pizza cost $8. Each additional inch cost

Katyanochek1 [597]

A pizza shop sells pizzas that are 10 inches orr larger. A 10-inch cheese pizza costs $8 and each additional costs $1.50 and each additional topping costs $0.75.

The equation that represents the cost of a pizza is:

P = $10 + $1.50a + $0.75b

Where 'a' represents the number additional inches and 'b' represents the number of additional toppings.

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2 years ago

What properties would you use to solve x/3=12 (multiple choice)

butalik [34]

C

explanation : the equation is division and since you don’t know what the variable x is, you multiply 3 and 12 to find x

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3 years ago

Is KLMN below a rectangle?

8_murik_8 [283]

Should be C right? A rectangle demands that the diagonals are congruent

6 0

3 years ago

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

2 years ago