Square root of 18 to the power of 2 plus 24 to the power of 2

Andrei [34K]

12. Divide total weight by weight of each. 1200 / 1.2 = 1000.
13. Total gas divided by number of cars will give amount of gas per car. 1350 / 100 = 13.5
14. The recipe gives the amount for 10 large bags. In other words, there is 750.2 grams in 10 bags. So divide by 10 to get the amount in 1 bag, which is B

15. Do the same process from 14. for oats and sunflowers, and then add them together. Answer is A
16. This is a bit diffrent but similar idea. Recipie gives for 100 snack sizes. So if we divided sunflower by tht we get 4.505. We need 2 bags however for a total of 9.01 grams. which is D

3 0

3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

HELP PLEASE HELP!!!!!

bagirrra123 [75]

(i): A triangle where all three sides are equal and the same.

(ii): A triangle where all three sides are unequal in length.

(iii): A triangle that has two sides of equal length.

(iv): A triangle where all three internal angles are acute(they measure less than 90 degrees.

(v): A triangle where all three internal angles are obtuse(measure above 90 degrees).

(vi): A triangle where one internal angle is a right angle(90 degrees).

Hope this helps

3 0

2 years ago

Read 2 more answers

Solve the Equation<br> -21 = 1/2c - 11

larisa [96]

Answer:

c = -20

Step-by-step explanation:

-21=1/2c-11

-21+11=1/2c

-10=1/2c

-10*2=c

-20=c

6 0

3 years ago

Read 2 more answers

Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)

morpeh [17]

Answer:

$\forall x\in D$ if x is odd then x> 0 is true statement.

$\forall x\in D$ if x is even then x≤0 is false statement.

$\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

$\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) $\forall x\in D$ if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

$\forall x\in D$ if x is odd then x> 0 is true statement.

Part (B) $\forall x\in D$ if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

$\forall x\in D$ if x is odd then x> 0 is true statement.

Part (C) $\forall x\in D$ if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

$\forall x\in D$ if x is even then x≤0 is false statement.

Part (D) $\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

$\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) $\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

$\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0

3 years ago