So when you factor this the answer would be (1w - 3)(5w + 1) because since 5 is an odd number you have to break it up with us only factores then you find the GCF for 3 and then you have to find the signs that when you multiply them it gives you - 14
I’m sorry this is hard:.(
Answer:
x = -2 and y = 3
{y = -3 x - 3, y = (3 x)/4 + 9/2} = x = -2 and y = 3
Step-by-step explanation:
Solve the following system:
{6 x + 2 y = -6
3 x - 4 y = -18
Express the system in matrix form:
(6 | 2
3 | -4)(x
y) = (-6
-18)
Solve the system with Cramer's rule:
x = -6 | 2
-18 | -4/6 | 2
3 | -4 and y = 6 | -6
3 | -18/6 | 2
3 | -4
Evaluate the determinant 6 | 2
3 | -4 = -30:
x = -6 | 2
-18 | -4/(-30) and y = 6 | -6
3 | -18/(-30)
Simplify -6 | 2
-18 | -4/(-30):
x = -1/30 -6 | 2
-18 | -4 and y = 6 | -6
3 | -18/(-30)
Simplify 6 | -6
3 | -18/(-30):
x = -(-6 | 2
-18 | -4)/30 and y = -1/30 6 | -6
3 | -18
Evaluate the determinant -6 | 2
-18 | -4 = 60:
x = (-1)/30×60 and y = -(6 | -6
3 | -18)/30
(-1)/30×60 = -2:
x = -2 and y = -(6 | -6
3 | -18)/30
Evaluate the determinant 6 | -6
3 | -18 = -90:
x = -2 and y = (-1)/30×-90
(-1)/30 (-90) = 3:
Answer: x = -2 and y = 3
___________________________________________
Solve the following system:
{y = -3 x - 3
y = (3 x)/4 + 9/2
Express the system in standard form:
{3 x + y = -3
-(3 x)/4 + y = 9/2
Express the system in matrix form:
(3 | 1
-3/4 | 1)(x
y) = (-3
9/2)
Write the system in augmented matrix form and use Gaussian elimination:
(3 | 1 | -3
-3/4 | 1 | 9/2)
Add 1/4 × (row 1) to row 2:
(3 | 1 | -3
0 | 5/4 | 15/4)
Multiply row 2 by 4/5:
(3 | 1 | -3
0 | 1 | 3)
Subtract row 2 from row 1:
(3 | 0 | -6
0 | 1 | 3)
Divide row 1 by 3:
(1 | 0 | -2
0 | 1 | 3)
Collect results:
Answer: {x = -2
, y = 3
Answer:
4.24 (OR JUST 4.2)
Step-by-step explanation:
Equation=15+3 (square root)
15+3=18
find square root of 18= 4.24 (or 4.2)
Answer:
126 different symbols can be represented in Morse code
Step-by-step explanation:
We need to sum up the number of sequences using one single place, two places, three places, four places and so on until sequences of six places (dots and dashes).
For each case we use the fundamental counting principle.
For one single place we may have 2 possible sequences (a dash or a dot)
For two places (example: .. or ._) we may have 2*2 sequences, since each place may be filled with either dash or dot (2 possible ways) and then we multiply the ways each place can be filled, thus
Similarly, for three places we may have 2*2*2 sequences, thus
For four places we may have 2*2*2*2 sequences, thus
And so on.
So, notice the total up to arrangements of six symbols, is: